3.9x9.87
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1 answer:
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Answer:
The required specific heat is 196.94 joule per kg per °C
Step-by-step explanation:
Given as :
The heat generated = Q = 85.87 J
Mass of substance (m)= 34.8 gram = 0.0348 kg
Change in temperature = T2 - T1 = 34.29°C - 21.76°C = 12.53°C
Let the specific heat = S
Now we know that
Heat = Mass × specific heat × change in temperature
Or, Q = msΔt
Or, 85.87 = (0.0348 kg ) × S × 12.53°C
Or , 85.87 = 0.4360 × S
Or, S =
∴ S = 196.94 joule per kg per °C
Hence the required specific heat is 196.94 joule per kg per °C Answer
Answer:
0.12 miles is it flying per second.
Step-by-step explanation:
The distance d is related to time t in seconds is given by the equation as follows :
d =0.12 t
We need to find how many miles is it flying per second.
So, the speed of the airplane is 0.12 miles per second, Hence, 0.12 miles is it flying per second.