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Westkost [7]
3 years ago
13

Someone please please help me with this !

Mathematics
1 answer:
skelet666 [1.2K]3 years ago
3 0

Answer:

4y+x - 16 = 0

Step-by-step explanation:

Given the equaton y - 2 = 4 (x-1)

Get the slope of the line

y - 2 = 4x  - 4

y =  4x - 4 + 2

y = 4x - 2

Since y = mx+b for a line

mx = 4x

m = 4

Slope of a line perpendicular M = -1/4

If the line passes through the point (-4, 5)

The equation in point slope form is expressed as y-y0 = m(x-x0)

Substitute;

y - 5 = -1/4(x-(-4))

y - 5  = -1/4(x+4)

4(y-5) = -(x+4)

4y - 20 = -x-4

4y+x-20+4 = 0

4y+x - 16 = 0

This gives the required equation

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7 0
3 years ago
What is the factor of 25a2+b2?
Neko [114]

Answer:

(5a+b)⋅(5a−b)

Step-by-step explanation:

Changes made to your input should not affect the solution:

(1): "b2"   was replaced by   "b^2".  1 more similar replacement(s).

STEP

1

:

Equation at the end of step 1

 52a2 -  b2

STEP

2

:

Trying to factor as a Difference of Squares

2.1      Factoring:  25a2-b2

Theory : A difference of two perfect squares,  A2 - B2  can be factored into  (A+B) • (A-B)

Proof :  (A+B) • (A-B) =

        A2 - AB + BA - B2 =

        A2 - AB + AB - B2 =

        A2 - B2

Note :  AB = BA is the commutative property of multiplication.

Note :  - AB + AB equals zero and is therefore eliminated from the expression.

Check :  25  is the square of  5

Check :  a2  is the square of  a1

Check :  b2  is the square of  b1

Factorization is :       (5a + b)  •  (5a - b)

7 0
3 years ago
A point P is moving along the curve whose equation is y = \sqrt x . Suppose that x is increasing at the rate of 4 units/s when x
Mice21 [21]

Answer:3 units/s

Step-by-step explanation:

Given

y=\sqrt{x}

Point P lie on this curve so any general point on curve can be written as (x,\sqrt{x})

and \frac{\mathrm{d} x}{\mathrm{d} t}=4 units/s

Distance between Point P and (2,0)

P=\sqrt{(x-2)^2+(\sqrt{x}-0)^2}

P at x=3 P=2

rate at which distance is changing is

\frac{\mathrm{d} P}{\mathrm{d} t}=\frac{\mathrm{d} \sqrt{(x-2)^2+(\sqrt{x}-0)^2}}{\mathrm{d} t}

\frac{\mathrm{d} P}{\mathrm{d} t}=\frac{2x-3}{\sqrt{(x-2)^2+(\sqrt{x}-0)^2}}\times \frac{\mathrm{d} x}{\mathrm{d} t}

\frac{\mathrm{d} P}{\mathrm{d} t}=\frac{2\times 3-3}{2\times 2}\times 4=3 units/s

8 0
3 years ago
Could I get some help?
Liono4ka [1.6K]
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8 0
3 years ago
lily is making granola she uses almonds walnuts and pecans in tge ratio 4:3:8 lily uses 40ounces of pecans
lbvjy [14]
Well. im not 100% sure if this is correct. but what i did was did 5 x 8. which equals 40. so then i did 5 x 3. which equals 15. then i did 5 x 4. which equals 20. hopefully im correct. hope this helped! :)
7 0
3 years ago
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