Question

Someone please please help me with this !

Answer 1

Answer:

4y+x - 16 = 0

Step-by-step explanation:

Given the equaton y - 2 = 4 (x-1)

Get the slope of the line

y - 2 = 4x  - 4

y =  4x - 4 + 2

y = 4x - 2

Since y = mx+b for a line

mx = 4x

m = 4

Slope of a line perpendicular M = -1/4

If the line passes through the point (-4, 5)

The equation in point slope form is expressed as y-y0 = m(x-x0)

Substitute;

y - 5 = -1/4(x-(-4))

y - 5  = -1/4(x+4)

4(y-5) = -(x+4)

4y - 20 = -x-4

4y+x-20+4 = 0

4y+x - 16 = 0

This gives the required equation