Answer:
4y+x - 16 = 0
Step-by-step explanation:
Given the equaton y - 2 = 4 (x-1)
Get the slope of the line
y - 2 = 4x - 4
y = 4x - 4 + 2
y = 4x - 2
Since y = mx+b for a line
mx = 4x
m = 4
Slope of a line perpendicular M = -1/4
If the line passes through the point (-4, 5)
The equation in point slope form is expressed as y-y0 = m(x-x0)
Substitute;
y - 5 = -1/4(x-(-4))
y - 5 = -1/4(x+4)
4(y-5) = -(x+4)
4y - 20 = -x-4
4y+x-20+4 = 0
4y+x - 16 = 0
This gives the required equation
