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3 years ago

10

The LCD for 4/8 and 5/12 is _____.

1 answer:

Masja [62]3 years ago

7 0

Answer:

22/24

Step-by-step explanation:

You might be interested in

What is the solution to the proportion?<br> 5/x = 2/16

mixas84 [53]

Answer:

I believe the answer is X=40

Step-by-step explanation:

cross multiply 5*16 = X * 2

Multiply 5*16

80= X*2

Add '-2x' to each side of the equation

80 + -2x = 2x + -2x

Combine like terms

80 + -2x = 0

Add '-80' to each side of the equation.

80 + -80 + -2x = 0 + -80

Combine like terms: 80 + -80 = 0

0 + -2x = 0 + -80

-2x = 0 + -80

Combine like terms: 0 + -80 = -80

-2x = -80

Divide each side by '-2'.

x = 40

Simplifying

x = 40

Hope this helped :)

5 0

3 years ago

33 degrees, 87 degrees, x=?

zheka24 [161]

Answer:

60°

Step-by-step explanation:

180 - 33 - 187 = 60

4 0

3 years ago

Read 2 more answers

Hurricane winds can be as strong as 150 miles per hours. If stick carried by a hurricane wind is flying at 130 mph, how far ( in

slavikrds [6]

Answer:

I believe it's 6.5 hours

Step-by-step explanation:

130/20=6.5

Not sure tho.

3 0

3 years ago

Read 2 more answers

Chau's shop sells quarts of ice cream each day. How much is this in pints?

barxatty [35]

Answer:

One quart is 2 pints

Step-by-step explanation:

multiply the number of quarts by 2 to get the number of pints.

5 0

3 years ago

Find all of the equilibrium solutions. Enter your answer as a list of ordered pairs (R,W), where R is the number of rabbits and

zloy xaker [14]

Answer:

$(0,0)$ $(4000,0)$ and $(500,79)$

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine the equilibrium solutions

We have:

$\frac{dR}{dt} = 0.09R(1 - 0.00025R) - 0.001RW$

$\frac{dW}{dt} = -0.02W + 0.00004RW$

To solve this, we first equate $\frac{dR}{dt}$ and $\frac{dW}{dt}$ to 0.

So, we have:

$0.09R(1 - 0.00025R) - 0.001RW = 0$

$-0.02W + 0.00004RW = 0$

Factor out R in $0.09R(1 - 0.00025R) - 0.001RW = 0$

$R(0.09(1 - 0.00025R) - 0.001W) = 0$

Split

$R = 0$ or $0.09(1 - 0.00025R) - 0.001W = 0$

$R = 0$ or $0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

Factor out W in $-0.02W + 0.00004RW = 0$

$W(-0.02 + 0.00004R) = 0$

Split

$W = 0$ or $-0.02 + 0.00004R = 0$

Solve for R

$-0.02 + 0.00004R = 0$

$0.00004R = 0.02$

Make R the subject

$R = \frac{0.02}{0.00004}$

$R = 500$

When $R = 500$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 -2.25 * 10^{-5} * 500 - 0.001W = 0$

$0.09 -0.01125 - 0.001W = 0$

$0.07875 - 0.001W = 0$

Collect like terms

$- 0.001W = -0.07875$

Solve for W

$W = \frac{-0.07875}{ - 0.001}$

$W = 78.75$

$W \approx 79$

$(R,W) \to (500,79)$

When $W = 0$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 - 2.25 * 10^{-5}R - 0.001*0 = 0$

$0.09 - 2.25 * 10^{-5}R = 0$

Collect like terms

$- 2.25 * 10^{-5}R = -0.09$

Solve for R

$R = \frac{-0.09}{- 2.25 * 10^{-5}}$

$R = 4000$

So, we have:

$(R,W) \to (4000,0)$

When $R =0$ , we have:

$-0.02W + 0.00004RW = 0$

$-0.02W + 0.00004W*0 = 0$

$-0.02W + 0 = 0$

$-0.02W = 0$

$W=0$

So, we have:

$(R,W) \to (0,0)$

Hence, the points of equilibrium are:

$(0,0)$ $(4000,0)$ and $(500,79)$

4 0

3 years ago