The first step for solving this problem is to multiply both sides of the bottom equation by -3.
$\left \{ {{6x-9y=16} \atop {-6x + 9y = -21}} \right.$
Add the two equations together.
6x - 9y - 6x + 9y = 16 - 21
Eliminate the opposites.
-9y + 9y = 16 - 21
Remember that the sum of two opposites equals 0,, so the equation becomes the following:
0 = 16 - 21
Calculate the difference on the right side of the equation.
0 = -5
This means that the statement $\left \{ {{6x-9y=16} \atop {2x-3y=7}} \right.$ is false for any value of x and y. That means that the answer to your question is (x,y) ∈ ∅,, or no solution.
Let me know if you have any further questions.
:)

8 0

3 years ago

Is 1/9 >, <, or = {Negative} -4?

kvasek [131]

Answer:

1/9 > -4

because -4 is a negative no less than 0. whereas 1/9 is a positive no greater than 0.

So negative no can't be greater than positive no.

6 0

2 years ago