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Rainbow [258]
3 years ago
14

Jaxon has $65 in his savings account. He deposits $15 every week. His father also deposits $25 into the account every time Jaxon

mows the lawn. His savings account balance can be shown with the following expression: 65 + 15w + 25m Part A: Identify a coefficient, a variable, and a constant in this expression. (3 points) Part B: If Jaxon saves for 20 weeks and mows the lawn 3 times, how much will he have in his account? Show your work to receive full credit. (4 points) Part C: If Jaxon had $75 in his savings account, would the coefficient, variable, or constant in the expression change? Why? (3 points)
Mathematics
1 answer:
Grace [21]3 years ago
8 0
Part A:
A coefficient can be either '15' or '25'.
A variable can be either 'w' or 'm'.
A constant is 65.

Part B:
Simply substitute, or plug-in, the numbers and solve.
***Step 1:
65+15w+25m --> 65+15(20)+25(3)
You do this because you are substituting the 'w' for the number
of weeks that Jaxon saved up for, which is 20, and the 'm' for the number
of times that Jaxon mowed the lawn, which is 3.
***Step 2:
65+15(20)+25(3) --> 65+300+75
Begin to solve, using PEMDAS, or whichever acronym you learned.
Remember, if you are using PEMDAS, recall that the order is Parenthesis,
Exponents, Multiplication/Division (whichever comes first), and
Addition/Subtraction (whichever comes first). Here, I checked for parenthesis.
I did find parenthesis, however, they do not have any expressions inside of
them, meaning that these parenthesis are for multiplying, and not for stating
order. So, you skip parenthesis. Next, you check for exponents, which you
find none of, so you skip over that. Now, we get to multiplying/dividing, so
you multiply the 15 and the 20 to get 300, and the 25 and 3 to get 75.
***Step 3:
65+300+75 --> 440
Now, we get to addition. You simply add everything up to get your final
answer: $440.

Part C:
If Jaxon had $75, then yes, the coefficients would change.
By subtracting $65 from $75, we can see that the total amount of money
from Jaxon's deposits and his lawn-mowing money is $10. Jaxon already
deposits $15 a week, meaning that, while using the current equation, Jaxon
CANNOT have $75 in his bank account. We can change the equation
so that Jaxon is able to have $75 in his savings account. You can change
the coefficient of 15 to 10, and the other coefficient of 25 to 0.
Now Jaxon is able to have $75 in his savings account.
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Answer:

we conclude that the relationship between distance and time is NOT proportional.

Hence, she did not drive at a constant speed.

Step-by-step explanation:

We know that when 'y' varies directly with 'x', we get the equation

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y = kx

k = y/x

where 'k' is called the constant of proportionality.

In our case, the table shows the distance Allison drove on one day of her vacation.

Time (h)              1         2        3          4        5

Distance (mi)       55    100     165     280    250

using the equation

k = y/x

susbtitute y = 55, x = 1

k = 55/1 = 55

substitute y = 100, x = 2

k = y/x

k = 100 / 2 = 50

substitute y = 165, x = 3

k = y/x

k = 165 / 3 = 55

substitute y = 280, x = 4

k = y/x

k = 280 / 4 = 70

substitute y = 250, x = 5

k = y/x

k = 250 / 5 = 50

It is clear that the value of 'k' does not remain constant.

Therefore, we conclude that the relationship between distance and time is NOT proportional.

Hence, she did not drive at a constant speed.

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Charlene is a video game designer and wants to make sure that her games can be played on all types of screens. In order for the
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<h3>Answer:</h3>

C. The playable area has a width of 9 inches and a height of 6 inches.

<h3>Explanation:</h3>

There are a number of ways you can get there.

1. Check the answers to see which have the right area and aspect ratio.

  • A: area = 24 in² — does not match 54 in²
  • B: area = 54 in², aspect ratio 6:9 = 2:3 — does not match 3:2 aspect ratio
  • C: area = 54 in², aspect ratio 9:6 = 3:2 — <em>matches problem statement</em>
  • D: area = 121.5 in² — does not match 54 in²

2. If the screen were 3:2 (inches), its area would be 6 in². The area of 54 in² is 9 times that value, so the actual screen dimensions are √9 = 3 times 3:2. That is, they are width:height = 9:6 inches — matches selection C.

3. You can write equations for width and height and solve.

  • w/h = 3/2
  • wh = 54

Substituting w=3/2·h into the second equation gives

... (3/2)h·h = 54

... h² = 36 . . . . . multiply by 2/3

... h = √36 = 6 . . . . square root, result in inches . . . . matches selection C

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3 years ago
A box is to be constructed with a rectangular base and a height of 5 cm. If the rectangular base must have a perimeter of 28 cm,
Svetradugi [14.3K]

Answer:

The quadratic equation that best models the volume of the box (in terms of W) is:

70W-5W^2

Step-by-step explanation:

The perimeter of the rectangular base = 28cm

Perimeter of a rectangle = 2(L+W)

2(L+W)=28

L+W=14

L=14-W

Volume of the Box= LWH

Since L=14-W and Height Of the Box= 5cm

Volume of the Box= (14-W)W X 5

=5(14W-W^2)\\                             =70W-5W^2

6 0
3 years ago
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