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trapecia [35]
3 years ago
11

When can you use mixed numbers in real life

Mathematics
1 answer:
ch4aika [34]3 years ago
3 0

Answer:

You can use mixed numbers in the real world when you are baking there are measuring cups like for example... 1 1/2 of sugar. You can also use mixed numbers in the real world when you are sharing thins like cake or a pizza. You can use mixed numbers for some things.

I did that picture for homework hope that helped .

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75% of the temperatures are below what value? How do you know? 75% of the temperatures are above what value? How do you know? Wh
Savatey [412]

Answer:

Complete Question:

Pick a city in Maryland and determine the average high temperatures for each month. Record this in a table.

a. Create a box-and-whisker plot for the data.

b. What is the median temperature?

c. 75%of the temperatures are below what value?How  do you know? d. 75% of the temperatures are above what value? How do you know? e. What conclusions can you draw about the temperature in Maryland?

Step-by-step explanation:

TASK 3

The city picked is Baltimore, the year 2017.

The table is attached in picture #1.

a) The box-and-whisker plot is attached in picture #2.

b) The median is the central value of the distribution i.e:  

42.4, 45.3, 46.8 | 54.7, 57.6, 66.0 | 69.1,  76.5,  80.6 | 85.8, 87.8, 90.0 

where we marked with a tally the quartiles.

As we have 12 values,  the average between the two central values will be the median :

M = (66.0 + 69.1) / 2 = 67.1 °F

c) 75% of the temperatures are below 83.2 °F.

Indeed, this value represents the third quartile. The position of the third quartile can be found by the formula:

3/4 · (n + 1) = 3/4 · (12 + 1) = 3/4 · 13 = 9.75

Therefore, since we did not get in integer position, the third quartile will be the average between the numbers in position 9 and 10:

q₀.₇₅ = (80.6 + 85.8) / 2 = 83.2 °F

d) 75% of the temperatures are above 50.8 °F.

Indeed, this value represents the first quartile. Similarly to point c), the position can be found by the formula:

1/4 · (n + 1) = 1/4 · 13 = 3.25

And therefore:

q₀.₂₅ = (46.8 + 54.7) / 2 = 50.8 °F. 

e) Baltimore in 2017 had a median high temperature of 67.1 °F.

25% of the year the high temperatures were warmer than 83.2 °F, with no outlier above 90.0 °F which was the hottest temperature.

25% of the high temperatures were colder than 50.8 °F, with no outlier below 42.4 °F, which was the coldest high temperature.

6 0
3 years ago
A junior college is going to choose a Homecoming Queen, and the candidates are the Freshman Queen and the Sophomore Queen. If th
KonstantinChe [14]
Count the votes, counting each sophomore ballot as 1.5 votes and each freshmen ballot as 1 vote.
ur doing this because there is 200 more freshmen then sophomores...and if u count each sophomore vote as 1.5, it would make up for the 200 more freshmen
5 0
3 years ago
Solve for P<br><br> I am so confused
Jlenok [28]

Answer:

3q/2

Step-by-step explanation:

3p+3q=p

2p=-3q

p=-3q/2

4 0
3 years ago
Read 2 more answers
(: Please answer both questions :)<br>First person gets 50 points!
Lemur [1.5K]

Answer:

1. 1350

2.2700

Step-by-step explanation:

4 0
3 years ago
A cooler has 12 apple juices and 15 grape juices. 9 of the apple juices are sugar free and 5 of the grape juices are sugar free.
Romashka-Z-Leto [24]

Answer:

<em>The probability that it is grape juice, given that the juice is not sugar free is </em><em>0.769 or 76.9%</em>

Step-by-step explanation:

P(\text{Grape }|\text{ Not sugar free})=\dfrac{P(\text{Grape }\cap \text{ Not sugar free})}{P(\text{Not sugar free})}

A cooler has 12 apple juices and 15 grape juices. So total 27 juices are there.

Out of 12 apple juices, 9 of the apple juices are sugar free, so 3 are not sugar free.

Out of 15 grape juices, 5 of the grape juices are sugar free, so 10 are not sugar free. So,

P(\text{Grape }\cap \text{ Not sugar free})=\dfrac{10}{27}

P(\text{Not sugar free})=\dfrac{10+3}{27}=\dfrac{13}{27}

Putting the values,

P(\text{Grape }|\text{ Not sugar free})=\dfrac{P(\text{Grape }\cap \text{ Not sugar free})}{P(\text{Not sugar free})}=\dfrac{\frac{10}{27}}{\frac{13}{27}}=\dfrac{10}{13}=0.769

5 0
4 years ago
Read 2 more answers
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