Problem 8-32 You are conducting a reliability analysis for a new product. Based on prior testing with a similar product, you bel
ieve the Weibull failure-time distribution, with parameter lambda=.200 per year, applies. But you have no basis for establishing beta. Compute at a time span of 5 years (1) the failure rate and (2) the survival probability assuming that
(a) beta=0.1
failure rate=
survival probability=
(b) beta=1
failure rate=
survival probability=
(c) beta=1.9
failure rate=
survival probability=
(d) beta=2.2
failure rate=
survival probability=
(a) beta=0.1
failure rate=
survival probability=
(b) beta=1
failure rate=
survival probability=
(c) beta=1.9
failure rate=
survival probability=
(d) beta=2.2
failure rate=
survival probability=
1 answer:
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The probability that the John either hits a Bull’s eye or scores 10 points in the game of darts is 2/5.
<h3>What is probability?</h3>Probability of an event is the ratio of number of favorable outcome to the total number of outcome of that event. The probability of an event can not be more than the number 1.
John is playing a game of darts. In this game of dart,
- The probability that he throws a dart into the center of the dart board (the Bull’s eye) is 1/10.
- The probability that he throws the dart into the 10-point ring is 3/10.
The probability that he either hits a Bull’s eye or scores 10 points is equal to the sum of the probability he hits the bull's eye and the probability that he throws the dart into the 10-points ring.
Let, the probability that he either hits a Bull’s eye or scores 10 points is P. Thus,
Hence, the probability that the John either hits a Bull’s eye or scores 10 points in the game of darts is 2/5.
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