All categories

2 years ago

Solve for x y=×/c+b

1 answer:

6 0

$\text{Hello there!}\\\\\text{Solve for x:}\\\\y=\frac{x}{c}+b\\\\\text{Multiply both sides by c to cancel the c out of the denominator}\\\\yc=x+bc\\\\\text{Subtract both sides by bc}\\\\yc-b=x\\\\\boxed{\text{Answer: yc - bc = x}}$

You might be interested in

A system contains n atoms, each of which can only have zero or one quanta of energy. How many ways can you arrange r quanta of e

My name is Ann [436]

Answer:

$\mathbf{a)} 2\\ \\ \mathbf{b)} 184 \; 756 \\ \\\mathbf{c)} \dfrac{(2\times 10^{23})!}{(10^{23}!)(10^{23})!}$

Step-by-step explanation:

If the system contains $n$ atoms, we can arrange $r$ quanta of energy in

$\binom{n}{r} = \dfrac{n!}{r!(n-r)!}$

ways.

$\mathbf{a)}$

In this case,

$n = 2, r=1$ .

Therefore,

$\binom{n}{r} = \binom{2}{1} = \dfrac{2!}{1!(2-1)!} = \frac{2 \cdot 1}{1 \cdot 1} = 2$

which means that we can arrange 1 quanta of energy in 2 ways.

$\mathbf{b)}$

In this case,

$n = 20, r=10$ .

Therefore,

$\binom{n}{r} = \binom{20}{10} = \dfrac{20!}{10!(20-10)!} = \frac{10! \cdot 11 \cdot 12 \cdot \ldots \cdot 20}{10!10!} = \frac{11 \cdot 12 \cdot \ldots \cdot 20}{10 \cdot 9 \cdot \ldots \cdot 1} = 184 \; 756$

which means that we can arrange 10 quanta of energy in 184 756 ways.

$\mathbf{c)}$

In this case,

$n = 2 \times 10^{23}, r = 10^{23}$ .

Therefore, we obtain that the number of ways is

$\binom{n}{r} = \binom{2\times 10^{23}}{10^{23}} = \dfrac{(2\times 10^{23})!}{(10^{23})!(2\times 10^{23} - 10^{23})!} = \dfrac{(2\times 10^{23})!}{(10^{23}!)(10^{23})!}$

3 0

3 years ago

Please helppp

tangare [24]

Answer:

Adult: 50 tickets

Child: 34 tickets

Step-by-step explanation:

Let a be the amount of adult tickets

Let c be the amount of child tickets

Equation:

a + c = 84

14a + 9c = 1,006

Step 1: Multiply a + c = 84 with -9, to canceled c.

-9 (a + c = 84) → -9a - 9c = -756

14a + 9c = 1006 → 14a + 9c = 1006

Step 2: Combined the 2 equation together, and solved it.

-9a - 9c = -756

14a + 9c = 1006

5a = 250

5 5

a = 50

Step 3: Plug 50 into the one of the equation, and solved it.

a + c = 84 → 50 + c = 84

-50 -50

c = 34

Answer: Adult tickets (a) = 50 and Child tickets (c) = 34

To check the answer plug the two number into the equation ( Make sure to add 50 for a and 34 for c).

3 0

2 years ago

74 rounded to the nearest whole number

ozzi

The answer is 70 . if it is 75 or higher then it wold be rounded to 80

5 0

3 years ago

please help:) thank youuuyy

Lana71 [14]

9514 1404 393

Answer:

x = 8
BF = 45

Step-by-step explanation:

Using the given information, we have ...

BH = 2·HF

3x +6 = 2(2x -1)

3x +6 = 4x -2

8 = x

The length of the median is ...

BF = BH + HF

BF = (3x +6) +(2x -1) = 5x +5

BF = 5·8 +5

BF = 45

6 0

2 years ago

WILL GIVE BRAINLST No hAVE A GOOD DAY

Simora [160]

Answer:

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Solve for x y=×/c+b​

Solve for x y=×/c+b