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Artyom0805 [142]
3 years ago
6

Solve for x y=×/c+b​

Mathematics
1 answer:
Alex17521 [72]3 years ago
6 0

\text{Hello there!}\\\\\text{Solve for x:}\\\\y=\frac{x}{c}+b\\\\\text{Multiply both sides by c to cancel the c out of the denominator}\\\\yc=x+bc\\\\\text{Subtract both sides by bc}\\\\yc-b=x\\\\\boxed{\text{Answer: yc - bc = x}}

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Pls help the first one is done but use that one to do the other one
dexar [7]

Answer:

I got 107 ft. ² and D.........

5 0
3 years ago
3x+2y=2<br> Y=x-9<br><br> A) (4,-5)<br> B) (4,13)<br> C) (-5,4) <br> D) (20,11)
BlackZzzverrR [31]
Y = X - 9
so 3X +2Y = 2
will be 3X +2×(X-9) = 2
3X + 2X -18 = 2
5X = 2 + 18
5X = 20
X = 4
Y = X - 9
Y = 4-9
Y = -5
the answer will be A) (4,-5)
please mark me as brainlest
4 0
3 years ago
If s(x) = 2x2 + 3x - 4, and t(x) = x + 4 then s(x) · t(x) =
Paladinen [302]

Answer:

\large\boxed{s(x)\cdot t(x)=2x^3+11x^2+8x-16}

Step-by-step explanation:

s(x)=2x^2+3x-4,\ t(x)=x+4\\\\s(x)\cdot t(x)\\\\\text{use the distributive property:}\ a(b+c)=ab+ac\\\\s(x)\cdot t(x)=(2x^2+3x-4)(x+4)\\\\=(2x^2+3x-4)(x)+(2x^2+3x-4)(4)\\\\=(2x^2)(x)+(3x)(x)+(-4)(x)+(2x^2)(4)+(3x)(4)+(-4)(4)\\\\=2x^3+3x^2-4x+8x^2+12x-16\\\\\text{combine like terms}\\\\=2x^3+(3x^2+8x^2)+(-4x+12x)-16\\\\=2x^3+11x^2+8x-16

7 0
4 years ago
Which of the following expressions are equivalent to -\dfrac{2}{-13}−
Fynjy0 [20]

Answer:

Step-by-step explanation:

We are given:

     

      2

- ----------

    -13

Since a negative number (-2) divided by another negative number results in a positive number,

      2

  ----------

     13

Both Answers A and B are correct; the final value in each case is +2/13.

4 0
3 years ago
Read 2 more answers
The sum of a number and 7 is the same as double the number increased by 3
koban [17]
So, let’s represent the number as n:
n+7=2n+3
Subtract both sides by 3:
n+4=2n
Now by n:
2n=4
Divide:
n=2
The number is 2
4 0
3 years ago
Read 2 more answers
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