Using derivatives, it is found that regarding the tangent line to the function, we have that:
- The equation of the line is y = 962x - 5119.
<h3>What is a linear function?</h3>
A linear function is modeled by:
y = mx + b
In which:
- m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.
- b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.
The slope of the line tangent to a function f(x) at x = x' is given by f'(x'). In this problem, the function is given by:
f(x) = 5x³ + 2x + 1.
The derivative is given by:
f'(x) = 15x² + 2.
Hence the slope at x = 8 is:
m = f'(8) = 15(8)² + 2 = 962.
The line goes through the point (8,f(8)), hence:
f(8) = 5(8)³ + 2(8) + 1 = 2577.
Hence:
y = 962x + b
2577 = 962(8) + b
b = -5119.
Hence the equation is:
y = 962x - 5119.
More can be learned about tangent lines at brainly.com/question/8174665
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Answer:
7:8
Step-by-step explanation:
Answer: 3.83
Step-by-step explanation:
(2.24)(1.71)
=3.83
I think you just simply solve it
Answer:
h(x) = x/2 - 1/2
Step-by-step explanation:
Here's the procedure for finding the inverse function algebraically:
1. Replace the label 'f(x)' with the label 'y:' y = 2x + 1
2. Interchange x and y: x = 2y + 1
3. Solve the resulting equation for y: 2y = x - 1, or y = (1/2)(x - 1) or y = x/2 - 1/2
This result corresponds to the 1st given possible answer choice.
The desired inverse function is h(x) = x/2 - 1/2
Answer:
Step-by-step explanation:
y = 6x − 4
y = 5x − 3
A: chose a value for x(input) and get the out put (y) because the equation already in the slope intercept mode:y=mx+b
x y=6x-4 y=5x-3
1 y=2 y=2
2 y=8 y=7
0 -4 -3
slope :
y=6x-4 slope is 6 y intercept(0,-4)
y=5x-3 slope is 5 y intercept (0,-3)
solution of the pair of equation is the point of intersection :
6x-4=5x-3
6x-5x=-3+4
x=1 and y=6x-4 ⇒ y=6-4=2
<h2>(1,2)</h2>
