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loris [4]
3 years ago
9

7x+y+3=y Graphing linear equations

Mathematics
1 answer:
PolarNik [594]3 years ago
5 0

Answer:

y=3.5x+1.5

Step-by-step explanation:

Move the y to the other side. 7x+3=2y

Divide by 2. 3.5x+1.5=y

Therefore the linear equation is y=3.5x+1.5

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An astronaut visited Mars. His weight on Earth was 180 pounds, and his weight on Mars was only 72 pounds. He removed a rock with
Damm [24]
Find the percentage of ratio to weight.

180/72 = 2.5

So 2.5 Earth Pounds = 1 Mars Pound

16*2.5 = 40 Pounds the rock weighs on earth.
5 0
3 years ago
ACTIVITY 2 (19) Mr Duma recently inherited a rectangular plot, part of the estate left by his late father. The plot with the fol
seraphim [82]

The sum of the lengths of three sides of the rectangle, gives the length

of the fencing, while one third of the rectangle area is for the pavement.

Responses:

Project A: The formula for the length of the fencing is, L = 4·x - 1

Project B: Length of the fancy wall = 2·x + 1

Project \ C:Area \ of \ the \ paving = \underline{ \dfrac{2\cdot x^2 }{3} - \dfrac{x }{3}  - \dfrac{1}{3}}

<h3>Which method can be used to find the length and area of paving from the given equations?</h3>

Project A: Let QP and SR represent the longest sides of the rectangle, we have;

PQ = SR = 2·x + 1

Given parameters are;

Length of the rectangular plot = 2·x + 1

Width of the rectangular plot = x - 1

Vertices of the rectangular plot are; QPSR

Project A: Let QP and SR represent the longest sides of the rectangle, we have;

PQ = SR = 2·x + 1

Which gives;

SP = QR = x - 1

The length of the fencing, L = SP + PQ + QR = x - 1 + 2·x + 1 + x - 1 = 4·x - 1

  • The formula for the length of the fencing is, L =<u> 4·x - 1</u>

Project B: The front side is SR

Therefore;

  • Length of the fancy wall = <u>2·x + 1</u>

Project C:

Area, A = Length × Width

Area of the plot, A = (2·x + 1) × (x - 1) = 2·x² - x - 1

  • Area \ of \ the \ paving = \dfrac{1}{3} \times \left(2 \cdot x^2 - x - 1\right) = \underline{ \dfrac{2\cdot x^2 }{3} - \dfrac{x }{3}  - \dfrac{1}{3}}

Learn more about writing equations here:

brainly.com/question/24760633

6 0
2 years ago
suppose 25 out of 175 people said they like to play disc golf and out 5 out of every twelve of the players have a personalized b
Serhud [2]
We have \frac{5}{12} of 252 people who have a personalized black disc

Number of people who would have personalized flying disc = \frac{5}{12}*252= \frac{2*252}{12}=105 people

Then we work out the number of people who like to play disc golf:
\frac{25}{175}*105= \frac{25*105}{175}=15 people

So we have 15 people who like to play disc golf and have personalised black disc.
8 0
3 years ago
PLEASE HELP!!!!!
Vesna [10]

Answer:

$289,169.84 (to the nearest cent)

Step-by-step explanation:

Compound interest is based on the principal amount and the interest that accumulates on it in every period.

Compound Interest = P (1 + r)^n

where P = principal amount, r = annual interest rate (as a decimal), n = term, in years​

So for this problem:

P = 185000

r = 1.4 ÷ 100 = 0.015

n = 30

Therefore,  

Compound Interest = P (1 + r)^n

                                = 185000 x (1 + 0.015)^30

                                = 185000 x (1.015)^30

                                = 289169.8408...

                                = $289,169.84 (to the nearest cent)

5 0
2 years ago
Consider the following graph, which details the observed bear population in two national parks. A graph titled Bears Observed in
damaskus [11]

Answer:

b. II and III

Step-by-step explanation:

A graph is a data presentation that has two axis - x and y, divided into appropriate scales.

A scale is used to divide given units into equal parts. It is crucial to and used to create uniformity in drawing of graphs. Choosing a good scale to represent an information on a graph is vital to avoid confusion. This can be done by considering the variations in the values forming the data.

In the question, the single graph shows an information about the bear population in two national parks. Thus, the scale of the y-axis must be adjusted and the identity of the two parks be more differentiated so as to make the graph less misleading.

6 0
3 years ago
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