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loris [4]
4 years ago
9

7x+y+3=y Graphing linear equations

Mathematics
1 answer:
PolarNik [594]4 years ago
5 0

Answer:

y=3.5x+1.5

Step-by-step explanation:

Move the y to the other side. 7x+3=2y

Divide by 2. 3.5x+1.5=y

Therefore the linear equation is y=3.5x+1.5

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Norma-Jean [14]

Remember the laws of exponents:

\frac{a^n}{a^m}=a^{n-m}

Then:

\begin{gathered} \frac{3^{100}}{3^{99}}=3^{100-99} \\ =3^1 \\ =3 \end{gathered}

Therefore:

\frac{3^{100}}{3^{99}}=3

7 0
1 year ago
Ernest earned $8.55 per hour plus an additional $90 in tips waiting tables on Friday. He earned at least $160 in all.
kvasek [131]

What are you trying to find?

6 0
3 years ago
Which answer is an equation in point-slope form for the given point and slope?
iren [92.7K]
Your answer will be b.
3 0
3 years ago
Read 2 more answers
What is the product? Assume x ≠ 0. 2x^2/3{6/x} 3x 4x 3x2 4x2
Serjik [45]

Answer:

4x

Step-by-step explanation:

The given product is;

\frac{2x^2}{3}(\frac{6}{x})

This is the same as;

\frac{2x^2\times 6}{3\times x}

We cancel out the common factors to obtain;

\frac{2x\times 2}{1\times 1}

Multiply out to obtain;

\frac{4x}{1}

Simplify

4x

The second option is the correct choice.

7 0
3 years ago
Read 2 more answers
g Two out of thirteen members of a school board feel that all high school students should be required to take a course in coding
denis-greek [22]

Answer:

There is a probability of 48.73% that at least one of the members polled favors requiring the​ course

Step-by-step explanation:

For each member asked, there are only two possible outcomes. Either they feel that all high school students should be required to take a course in coding, of they feel they shouldn't. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

Four members are selected, so n = 4.

Two out of thirteen members of a school board feel that all high school students should be required to take a course in coding. This means that p = \frac{2}{13} = 0.1538.

What is the probability that at least one of the members polled favors requiring the​ course?

Either none of them favor requiring the course, or at least one do. The sum of the probabilities of these events is decimal 1. So:

P(X = 0) + P(X > 0) = 1

P(X > 0) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{4,0}.(0.1538)^{0}.(0.8462)^{4} = 0.5127

So

P(X > 0) = 1 - P(X = 0) = 1 - 0.5127 = 0.4873

There is a probability of 48.73% that at least one of the members polled favors requiring the​ course

5 0
3 years ago
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