Answer:
Genotype of the father: Heterozygous dominant (Aa)
Explanation:
Let's suppose allele "a" is responsible for albinism while allele "A" gives normal phenotype.
Given that Albinism is a recessive trait, it will be expressed in a homozygous recessive genotype only. The female snake is albino and hence, her genotype is= "aa".
Since the progeny have both normal and albino snake, the male parent should be heterozygous dominant (Aa) with one copy of normal allele and one copy of recessive allele.
CTATA GGAAG ATGGA. Switch Cs to Gs vice versa. Switch Ts to As vice versa.
I believe that the answer is B. a fertilized egg splits in two but I could be wrong
Answer: The corresponding mRNA sequence to the DNA strand will be
ATTGCGAATTC
Explanation:
Because nitrogenous bases specifically pair in the following order:
- Adenine pairs with Thymine
- Cytosine pairs with Guanine
mRNA also known as messenger RNA, which is complimentary to one strand of DNA will have its sequence as the "pairing base partner". Thus, the mRNA sequence is ATTGCGAATTC.