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Law Incorporation [45]
3 years ago
15

Marcia needs to paint all the faces and the base of a model of a pyramid she made for her history project. The dimensions of the

pyramid are shown. What is the total surface area of the pyramid?
A.135 in2
B.170 in2
C.240 in2
D.260 in2

Mathematics
1 answer:
Nata [24]3 years ago
4 0
That Would be C my friend hope this helped

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2(x + 1 ) - 3(x + 5) ≥ 0
zaharov [31]

answer is x is less than or equal to -13

hope this helps:-)

3 0
3 years ago
Read 2 more answers
F(x)=2(x)^2+5 sqrt (x+2)<br><br> f(0)
krek1111 [17]
F(0) = replace every x with 0

2 ({0})^{2}  + 5 \sqrt{0 + 2}  \\  = 2 + 5 \sqrt{2}
=9.0710678119
=9.07
7 0
3 years ago
Can you conclude that this parallelogram is a rectangle? Explain.
maxonik [38]

I think it yes the diagonals are congruent but I can’t really tell

5 0
3 years ago
Read 2 more answers
Find the value of y.y^2=169
wel

y^2=169

y = √169

y = + / - 13

Answer

y = -13 or y = 13

8 0
3 years ago
Thanks for your response!<br> Question will be show✔
algol13
<h3>Answer:</h3>

\large\boxed{-1\frac{16}{25},\,\frac{6}{40},\,0.35,\,1\frac{3}{4}}

<h3>Step-by-step explanation:</h3>

In this question, it's asking you to put the numbers that were given from <em>least </em>to <em>greatest.</em>

Our given numbers are:

  • \frac{6}{40}
  • 0.35
  • 1\frac{3}{4}
  • -1\frac{16}{25}

Now, lets sort them out.

We know that negative numbers would be the least. Sicne there's only one negative number, we would put that first because it's the least out of the numbers.

\frac{6}{40} would go next. To make it easier, we can turn it into a decimal. \frac{6}{40} = 0.15 when you divide.

0.35 will go next. This would be bigger than 0.15, but lower than the next number.

1\frac{3}{4} would go last, due to the fact that it's the greatest. 1\frac{3}{4} is the same as 1.75

When you put them in order, you should get -1\frac{16}{25},\,\frac{6}{40},\,0.35,\,1\frac{3}{4}

<h3>I hope this helped you out.</h3><h3>Good luck on your academics.</h3><h3>Have a fantastic day!</h3>
4 0
3 years ago
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