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3 years ago

Sarah sells 5 newspapers for $15 what is the unit rate for 1 newspaper

Mathematics

2 answers:

Elden [556K]3 years ago

8 0

Answer:

Step-by-step explanation:

15/3=15

so each newspaper cost $3

amm18123 years ago

3 0

Answer:

1 newspaper is 3 dollars

Step-by-step explanation:

the ratio 5:15 is equivalent to 1:3

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Answer:

⅓

Step-by-step explanation:

8+7+6

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<h2>135° angle</h2>

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2 years ago

Which picture shows the correct graph of |x|=3?

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2 years ago

How are addition properties and subtraction rules helpful when solving problems

snow_lady [41]

For the sum we have the following properties:
The properties are commutative, asosiative, distributive and neutral element.

Commutative property: When two numbers are added, the result is the same regardless of the order of the addends.

Associative property: When three or more numbers are added, the result is the same regardless of the order in which the addends are added.

Neutral element: The sum of any number and zero is equal to the original number.

Distributive property: The sum of two numbers multiplied by a third number is equal to the sum of each summand multiplied by the third number.

For subtraction we have:

 The arithmetic operation of the subtraction (subtraction) is indicated by the minus sign (-) and is the opposite, or inverse, operation of the addition. That is, it is an arithmetic operation that serves to find the difference between two numbers.

In subtraction A - B = D
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The properties of addition and subtraction serve to rewrite and simplify calculations.

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2 years ago

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If there is some scalar function $f(x,y)$ such that

$\nabla f(x,y)=\mathbf f(x,y)=x^2\,\mathbf i+y^2\,\mathbf j$

then we want to find $f$ such that

$\dfrac{\partial f}{\partial x}=x^2\implies f(x,y)=\dfrac{x^3}3+g(y)$
$\dfrac{\partial f}{\partial y}=y^2=\dfrac{\mathrm dg}{\mathrm dy}\implies g(y)=\dfrac{y^3}3+C$
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So the vector field $\mathbf f(x,y)$ is conservative, which means the fundamental theorem applies; the line integral of $\mathbf f$ along any path $\mathcal C$ parameterized by some vector-valued function $\mathbf r(t)$ over $a\le t\le b$ is given by

$\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=\int_{t=a}^{t=b}\mathbf f(\mathbf r(t))\cdot\dfrac{\mathrm d\mathbf r}{\mathrm dt}\,\mathrm dt=f(\mathbf r(b))-f(\mathbf r(a))$

In this case,

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