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3 years ago

Sarah sells 5 newspapers for $15 what is the unit rate for 1 newspaper

Mathematics

2 answers:

Elden [556K]3 years ago

8 0

Answer:

Step-by-step explanation:

15/3=15

so each newspaper cost $3

amm18123 years ago

3 0

Answer:

1 newspaper is 3 dollars

Step-by-step explanation:

the ratio 5:15 is equivalent to 1:3

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The sum of two numbers is 21,and their difference is 9

Ghella [55]

let's say the two numbers are x and x + 9. so we know x + x + 9 = 21, so 2x + 9 = 21. subtract 9 from both dies to get 12 = 2x. divide both sides by 2 to get x = 6. so your two numbers are 6 and 15.

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3 years ago

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The price of a computer after discount was $850. If the discount was 25%, what was the original price of the computer?

malfutka [58]

Answer:

21.25

Step-by-step explanation:

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2 years ago

How can Ari simplify the following expression? StartFraction 5 Over a minus 3 EndFraction minus 4 divided by 2 + StartFraction 1

kirill [66]

Answer:

The simplification for the expression is given as =( 7 + 2(a-3))/(a-3)

Step-by-step explanation:

To simplify the expression we will first convert the words to values in numbers and alphabets.

StartFraction 5 Over a minus 3 EndFraction minus 4 divided by 2 + StartFraction 1 Over a minus 3 EndFraction

= 5/(a-3) -4/2 + 2/(a-3)

Having done that, let's move on and simplify the expression.

5/(a-3) -4/2 + 2/(a-3)

= 5/(a-3) -2+ 2/(a-3)

= 5/(a-3) + 2/(a-3) -2

= 7/(a-3) -2

=( 7 + 2(a-3))/(a-3)

7 0

3 years ago

Find the area of the shape shown<br> below.

asambeis [7]

Answer:

the area is six units squared

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3 years ago

A rocket is launched straight up from the ground with an initial velocity of 192 feet per second. The equation for the height of

Ivenika [448]

The equation for the height of the rocket at time t given

$h= -16t^2+192t$

We have to find the time t, when the rocket reaches 560 feet.

That means we have to find t when h = 560 ft. we will place 560 in the place of h to find t now.

$h= -16t^2+192t$

$560 = -16t^2+192t$

In the right side, we can check -16 is the common factor. So we will take out -16 from the rigbht side.

$560 = -16(t^2 - 12t)$

To get rid of -16 from the right side and move it to left side, we will divide both sides by -16.

$560/-16 = -16(t^2-12t)/-16$

$-35 = t^2 -12t$

Now we will move -35 to the righ side by adding 35 to both sides.

$-35+35 = t^2-12t+35$

$0 = t^2 -12t+35$

$t^2-12t+35 = 0$

We will factorize thee left side to find the values of t now. We need to find a pair of factors of 35 that by adding them we will get -12.

The pair of factors of 35 are -5 and -7 and by adding -5-7 we will get -12.

$t^2-12t+35 =0$

$(t-5)(t-7) =0$

So by using zero product property we will get

$t-5 =0$

$t-5+5 = 0+5$

$t=5$

Also $t-7 =0$

$t-7+7 = 0+7$

$t=7$

So we have got the rocket reaches at 560ft when t = 5 seconds and also when t = 7 seconds.

Now part b.

When the rocket completes its trajectory and hits the ground then the height or h = 0. So we will place h = 0 there in the equation.

$h= -16t^2+192t$

$0= -16t^2 + 192 t$

$0 = -16(t^2-12t)$

$-16(t^2-12t) = 0$

We will move -16 to the other side by dividing it to both sides.

$-16(t^2-12t)/-16 = 0/-16$

$t^2-12t = 0$

We will take out the common factor t from the left side. By taking out t we will get,

$t(t-12) = 0$

We will use zero product property now. By using that we will get,

$t = 0$

ans also $t-12 = 0$

$t-12+12 = 0+12$

$t = 12$

When the rocket completes its trajectory and hits the ground the time t can not be 0. When t =0, the rocket starts the trajectory.

So when the rocket completes its trajectory and hits the ground ,

then t = 12seconds.

So we have got the required answers.

6 0

2 years ago