Answer:
1.No, 143 is not a prime number. The list of all positive divisors the list of all integers that divide 143 is as follows: 1, 11, 13, 143. To be 143 a prime number, it would have been required that 143 has only two divisors, itself and 1.
2.Since the polynomial can be factored, it is not prime.
(4v-3w)∧2, Its to the second power so take the exponent 2 and put it on the variables and coefficients so you would have (4∧2)(v∧2)-(3∧2)(w∧2). Then you would do the math and get 16v∧2-9w∧2 than you would add the like terms so you have 25v∧2w∧2.
The exponents of expression one are the same as the exponents of expression two
Answer:
40(x-10)
Step-by-step explanation: