The distance from the center to where the foci are located exists 8 units.
<h3>How to determine the distance from the center?</h3>
The formula associated with the focus of an ellipse exists given as;
c² = a² − b²
Where c exists the distance from the focus to the center.
a exists the distance from the center to a vertex,
the major axis exists 10 units.
b exists the distance from the center to a co-vertex, the minor axis exists 6 units
c² = a² − b²
c² = 10² - 6²
c² = 100 - 36
c² = 64
c = 8
Therefore, the distance from the center to where the foci are located exists 8 units.
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Answer: $5.54
Step-by-step explanation: 63 divided by 100 is 0.63, 0.63 x 8.8 is 5.544 and 5.544 rounded to the nearest cent is $5.54
Step-by-step explanation:
Applying the linear pair theorem, the measure of angle TSV in the image given is: 86°.
<h3>How to Apply the Linear Pair Theorem?</h3>
Given the following angles in the image above:
Measure angle RSU = (17x - 3)°,
Measure angle UST = (6x – 1)°
To find the measure of angle TSV, we need to find the value of x in the given expressions as shown below:
m∠RSU + m∠UST = 180 degrees (linear pair]
Substitute the values
17x - 3 + 6x - 1 = 180
Solve for x
23x - 4 = 180
23x = 180 + 4
23x = 184
x = 8
m∠TSV = 180 - 2(m∠UST) [Linear Pair Theorem]
m∠TSV = 180 - 2(6x - 1)
Plug in the value of x
m∠TSV = 180 - 2(6(8) - 1)
m∠TSV = 86°
Therefore, applying the linear pair theorem, the measure of angle TSV in the image given is: 86°.
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Answer:
The transformation is left 1 hope it is right
Step-by-step explanation:
