Speed of the plane: 250 mph
Speed of the wind: 50 mph
Explanation:
Let p = the speed of the plane
and w = the speed of the wind
It takes the plane 3 hours to go 600 miles when against the headwind and 2 hours to go 600 miles with the headwind. So we set up a system of equations.
600
m
i
3
h
r
=
p
−
w
600
m
i
2
h
r
=
p
+
w
Solving for the left sides we get:
200mph = p - w
300mph = p + w
Now solve for one variable in either equation. I'll solve for x in the first equation:
200mph = p - w
Add w to both sides:
p = 200mph + w
Now we can substitute the x that we found in the first equation into the second equation so we can solve for w:
300mph = (200mph + w) + w
Combine like terms:
300mph = 200mph + 2w
Subtract 200mph on both sides:
100mph = 2w
Divide by 2:
50mph = w
So the speed of the wind is 50mph.
Now plug the value we just found back in to either equation to find the speed of the plane, I'll plug it into the first equation:
200mph = p - 50mph
Add 50mph on both sides:
250mph = p
So the speed of the plane in still air is 250mph.
Answer:
May be i think answer is 7
A) 1000/239 = 4.something
Ms. Ferguson could book the room for 4 nights
B) 6 x 239 = 1434
1450/1434 = 1.01
Ms Ferguson was off by 1%
C) 2075/1589 = 1.3058
The price increase was by 31%
D) 2075/1.3 = 1596.153
The price that was found was $1596.15
Answer:
A, C, E, F, G
Step-by-step explanation:
let's actually solve the inequality -7x+14>-3x-6:
Adding 7x to both sides simplifies the inequality to 14> 4x-6.
Adding 6 to both sides isolates 4x: 20 > 4x.
Finally, dividing both sides by 4 yields 5 > x, or x < 5.
We must now determine which of the possible solutions A-G are less than 5:
A, C, E, F, G
<u>Answer: </u>
sec squared 55 – tan squared 55 = 1
<u>Explanation:</u>
Given, sec square 55 – tan squared 55
We know that,
And,
where Ө is the angle
Substituting the values
Solving,
According to Pythagoras theorem,
Putting this in the equation;
squared 55 - tan squared 55 =
Therefore, sec squared 55 – tan squared 55 = 1