when is the population standard deviation greater than the population variance? a. when the variance is less than 1 b. when the
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Okay, the exponential function is
The start price of it in t=0 is 3,500, as we can see on the graph. Then, the function becomes
Let's see at t=2, where the price is g=2000:
Take natural logarithm:
So, the difference between t=0 and t=2 is
And then we get the change of x in one year equal to 0.035.
So, the final equation is
You can insert any t and see that it is correct, for example t=7
The start price of it in t=0 is 3,500, as we can see on the graph. Then, the function becomes
Let's see at t=2, where the price is g=2000:
Take natural logarithm:
So, the difference between t=0 and t=2 is
And then we get the change of x in one year equal to 0.035.
So, the final equation is
You can insert any t and see that it is correct, for example t=7
First, we can simplify it down.
x = (-x + 6)^2
Then, you should have x - (
- 12x + 36).
Factor it to get x = 4 or 9. 4 works in the original equation but 9 does not.
x = (-x + 6)^2
Then, you should have x - (
Factor it to get x = 4 or 9. 4 works in the original equation but 9 does not.