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Hatshy [7]
3 years ago
12

A ship traveled for 4 hours heading east and for 3 hours heading north. If the total distance traveled was 149 miles, and the sh

ip traveled 3 miles per hour faster heading north, at what speed was the ship traveling east?
Mathematics
1 answer:
Alex3 years ago
8 0
D=vt,   distance is equal to velocity times time.

4v+3(v+3)=149 perform indicated multiplication

4v+3v+9=149  combine like terms on left side

7v+9=149  subtract 9 from both sides

7v=140  divide both sides by 7

v=20

So the ship traveled at a speed of 20 mph when heading east.
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4 years ago
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RoseWind [281]

Answer:

a_n=2+3n

\displaystyle S_n=\frac{7n+3n^2}{2}

Step-by-step explanation:

<u>Arithmetic Sequences </u>

The arithmetic sequences are identified because any term n is obtained by adding or subtracting a fixed number to the previous term. That number is called the common difference.

The equation to calculate the nth term of an arithmetic sequence is:

a_n=a_1+(n-1)r

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The sum of the n terms of an arithmetic sequence is given by:

\displaystyle S_n=\frac{a_1+a_n}{2}\cdot n

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Thus the general term of the sequence is:

a_n=5+(n-1)3=5+3n-3=2+3n

\boxed{a_n=2+3n}

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