A ship traveled for 4 hours heading east and for 3 hours heading north. If the total distance traveled was 149 miles, and the sh
ip traveled 3 miles per hour faster heading north, at what speed was the ship traveling east?
1 answer:
D=vt, distance is equal to velocity times time.
4v+3(v+3)=149 perform indicated multiplication
4v+3v+9=149 combine like terms on left side
7v+9=149 subtract 9 from both sides
7v=140 divide both sides by 7
v=20
So the ship traveled at a speed of 20 mph when heading east.
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