All categories

3 years ago

In triangle abc shown below side ab is 6 and side ac is 4

Mathematics

1 answer:

kaheart [24]3 years ago

7 0

Question is Incomplete, Complete question is given below:

In Triangle ABC shown below, side AB is 6 and side AC is 4.

Which statement is needed to prove that segment DE is parallel to segment BC and half its length?

Answer

Segment AD is 3 and segment AE is 2.

Segment AD is 3 and segment AE is 4.

Segment AD is 12 and segment AE is 4.

Segment AD is 12 and segment AE is 8.

Answer:

Segment AD is 3 and segment AE is 2.

Step-by-step explanation:

Given:

side AB = 6

side AC = 4

Now we need to prove that segment DE is parallel to segment BC and half its length.

Solution:

Now AD + DB = AB also AE + EC = AC

DB = AB - AD also EC = AC - AE

Now we take first option Segment AD is 3 and segment AE is 2.

Substituting we get;

DB = 6-3 = 3 also EC = 4-2 =2

From above we can say that;

AD = DB and EC = AE

So we can say that segment DE bisects Segment AB and AC equally.

Hence From Midpoint theorem which states that;

"The line segment connecting the midpoints of two sides of a triangle is parallel to the third side and is congruent to one half of the third side."

Hence Proved.

You might be interested in

Need help thanks!!!!!!

kherson [118]

Answer:

Step-by-step explanation:

$-----------------------------$

$Here's$ $how$ $we$ $solve$ $the$ equation

$-1.2\left(3-x\right)$ = $-1.8$

$-1.2\left(3-1.5\right)$ = $-1.8$

$-3.6+1.2\cdot1.5$ = $-1.8$

$1.2\cdot1.5$ = $-1.8$

$-----------------------------$

<em>Hope this helps! <3</em>

5 0

2 years ago

An urn contains 5 red balls and 2 green balls. Two balls are drawn one after the other. What is the probability that the second

AleksAgata [21]

Answer:

<em>The probability that the second ball is red is 71%</em>

Step-by-step explanation:

<u>Probabilities</u>

We know there are 5 red balls and 2 green balls. Let's analyze what can happen when two balls are drawn in sequence (no reposition).

The first ball can be red (R) or green (G). The probability that it's red is computed by

$\displaystyle P(R)=\frac{5}{7}$

The probability is's green is computed by

$\displaystyle P(G)=\frac{2}{7}$

If we have drawn a red ball, there are only 4 of them out of 6 in the urn, so the probability to draw a second red ball is

$\displaystyle P(RR)=\frac{5}{7}\cdot \frac{4}{6}=\frac{10}{21}$

If we have drawn a green ball, there are still 5 red balls out of 6 in the urn, so the probability to draw a red ball now is

$\displaystyle P(GR)=\frac{2}{7}\cdot \frac{5}{6}=\frac{5}{21}$

The total probability of the second ball being red is

$\displaystyle P(XR)=\frac{10}{21}+\frac{5}{21}=\frac{5}{7}=0.71$

The probability that the second ball is red is 71%

7 0

3 years ago

Factorise fully − z − 9

NeX [460]

Answer:

Yes

Step-by-step explanation:

Question

4 0

2 years ago

What is the range of y =5/2(x-2)² - 4

blagie [28]

Answer:

vertex:(2,-4)

Focus:(2,- $\frac{39}{10}$ )

Axis of symmetry :x=2

Directrixt: y=- $\frac{41}{10}$

Step-by-step explanation:

7 0

3 years ago

If Rachel were to paint her living room alone, it would take 2 hours. Her sister Fran could do the job in 5 hours. How many hour

snow_tiger [21]

Rachel and her sister Fran together can paint the living room in $\frac{10}{7}$ hours

Given that

Rachel can paint half of the living room in 1 hour

Fran can paint $\frac{1}{5}$ th part of the living room in 1 hour

Let's assume together they paint the living room in x hours

⇒ together they can paint $\frac{1}{x}$ th part of the living room in 1 hour

By proportions,

⇒ $\frac{1}{2}$ + $\frac{1}{5}$ = $\frac{1}{x}$ {using operation proportions and addition}

⇒ $\frac{7}{10}$ = $\frac{1}{x}$

⇒x= $\frac{10}{7}$

⇒ together they can paint $\frac{7}{10}$ th part of the living room in 1 hour

It means, Rachel and her sister Fran together can paint the living room in $\frac{10}{7}$ hours

Learn more about paint here:

brainly.com/question/15277377

#SPJ9

6 0

1 year ago