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velikii [3]
3 years ago
8

Raul has 4/5 pound of modeling clay. He needs to divide the clay into bags that hold 1/10 pound each. How many bags will he fill

?
Mathematics
1 answer:
____ [38]3 years ago
5 0

Answer:

The Answer would be 8.

Step-by-step explanation:

I just did a quiz with this exact question

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Please help it urgent!!!!
Veronika [31]

Answer:

<h3>1) 5(7x^{2} - x + 8)</h3>

first box: 5 * 7 = 35

35 x^2

second box: 5 * -1 = -5

-5x

third box: 5 * 8 = 40

40

answer: 35x^{2} - 5x + 40

<h3>2) 2x(4x^2 + 3x + 6)</h3>

first box: 2x * 4x^2

2 * 4 = 8

x * x^2 = x^3

8x^3

second box: 2x * 3x

2 * 3 = 6

x * x = x^2

6x^2

third box: 2x * 6

2 * 6 = 12

12x

answer: 8x^3 + 6x^2 + 12x

<h3>3) (tp + 5)(4p - 6)</h3>

top left box: tp * 4p

p * p = p^2

4tp^{2}

top right box: tp * - 6

-6tp

bottom left box: 5 * 4p

5 * 4 = 20

20p

bottom right box: 5 * - 6

5 * -6 = -11

-11

answer: 4tp^2 - 6tp + 20p - 11

<h3>4) (4a - 8)(8a - 1)</h3>

top left box: 4a * 8a

4 * 8 = 32

a * a = a^2

32a^2

top right box: 4a * -1

4 * -1 = -4

-4a

bottom left box: -8 * 8a

-8 * 8 = -64

-64a

bottom right box: -8 * - 1

-8 * - 1 = 8

8

32a^2 - 4a - 64a + 8

<em>combine like terms</em>

32a^2 - 68a + 8 = answer

4 0
3 years ago
Given: <br> ΔABC, m∠C = 90º, m∠B = 30º<br> CM - angle bisector<br><br> Find: m∠AMC
SashulF [63]

Answer:

75°

Step-by-step explanation:

1. Consider right triangle ABC. In this triangle

m∠C = 90º and CM - angle bisector.

If CM is angle C bisector, then

m∠ACM = m∠MCB = 45º

2. Consider triangle CMB. The sum of the measures of all interior angles of the triangle is always 180°, then

m∠MCB + m∠CBM + m∠BMC = 180°,

m∠BMC = 180° - 45° - 30°

m∠BMC = 105°

3. Angles AMC and BMC are supplementary angles, so

m∠AMC + m∠BMC = 180°

m∠AMC = 180° - 105°

m∠AMC = 75°

3 0
3 years ago
Can you help me get this answer
scoundrel [369]

Answer:

y = f(x-1) - 3

is the correct function

3 0
2 years ago
A 9 inch candle burns -2/3 inch per hour. How long will it take the candle to burn completely?
Luda [366]
Gbbdnn sbxrbrndmndnsmxnnnbbbd
5 0
3 years ago
Read 2 more answers
Can anyone help me with Question 7? I’m not good at word problems :(
romanna [79]
You just have to find the angle whose sine is 0.1045. Use the sin-1 key on your calculator  ( make sure its set to degrees first)

m < B =  6.000 degrees to nearest thousandth
7 0
3 years ago
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