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lyudmila [28]
3 years ago
9

What is the slope of a line that is perpendicular to the line represented by x=3?

Mathematics
1 answer:
solmaris [256]3 years ago
4 0

Answer:

  1. 0
  2. (5, -2)

Step-by-step explanation:

1. The equation x=3 describes a vertical line. A perpendicular line will be horizontal. It will have no "rise" for any length of "run." The slope is zero.

__

2. The point-slope form of the equation for a line with slope m through point (h, k) is ...

  y -k = m(x -h)

You can read the values of h and k from your equation. They are ...

  • h = 5
  • k = -2

So, a point on the line is (h, k) = (5, -2).

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Given the information in the diagram below, find the measure of angle N. Use RACE and complete sentences to show how you found t
Sonja [21]

Answer:

m<N = 76°

Step-by-step explanation:

Given:

∆JKL and ∆MNL are isosceles ∆ (isosceles ∆ has 2 equal sides).

m<J = 64° (given)

Required:

m<N

SOLUTION:

m<K = m<J (base angles of an isosceles ∆ are equal)

m<K = 64° (Substitution)

m<K + m<J + m<JLK = 180° (sum of ∆)

64° + 64° + m<JLK = 180° (substitution)

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subtract 128 from each side

m<JLK = 180° - 128°

m<JLK = 52°

In isosceles ∆MNL, m<MLN and <M are base angles of the ∆. Therefore, they are of equal measure.

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m<MLN = 52°

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m<M = 52° (substitution)

m<N + m<M° + m<MLN = 180° (Sum of ∆)

m<N + 52° + 52° = 180° (Substitution)

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m<N = 180° - 104°

m<N = 76°

4 0
3 years ago
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