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KIM [24]
3 years ago
12

What are the coordinates of vertex J of the pre-image?

Mathematics
1 answer:
Dvinal [7]3 years ago
3 0
The figure is a rhombus J' K' L' M' in a coordinate plane, showing all its vertices.

The vertex J' is the point (0, -2).

And the statement indicates that the quadrilateral JKLM was transformed into the figure J'K'L'M' by the dilation (x,y) -> (x/2, y/2).

Then you have to find the preimag of J' which is J.

You know that x was multiplied by 1/2 to transform into 0, then x/2 = 0 => x =0

And y was mutilplied by 1/2 to transform into -2, then y/2 = -2 => y = -4.

And the pre-image is (0, -4)

Answer: (0, -4)
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We can convert 20km to 20,000m. Then, we can subtract 800m (walking distance) from 20,000m which would result in 19,200m. Then we can put 19,200m and 20,000m as a fraction (19200/20000). Before we can multiply it by 100 to make it in the percentage form, we can get rid of 2 zeroes for both number making it 192/200 and then further simplifying it to 24/25 by dividing both numbers by 8. Finally to get the percentage we can multiply 24 and 100 (2400) and then divide the result (2400) by 25. The final answer is 2400/25=96 meaning he cycled 96% of the journey and walked 4% of the journey (100-96=4).
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