What are the coordinates of vertex J of the pre-image?

Mathematics

1 answer:

Dvinal [7]3 years ago

3 0

The figure is a rhombus J' K' L' M' in a coordinate plane, showing all its vertices.

The vertex J' is the point (0, -2).

And the statement indicates that the quadrilateral JKLM was transformed into the figure J'K'L'M' by the dilation (x,y) -> (x/2, y/2).

Then you have to find the preimag of J' which is J.

You know that x was multiplied by 1/2 to transform into 0, then x/2 = 0 => x =0

And y was mutilplied by 1/2 to transform into -2, then y/2 = -2 => y = -4.

And the pre-image is (0, -4)

Answer: (0, -4)

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Step-by-step explanation:

We have a function notation for the transformation that would change f(x) to have a vertical compression by a factor of $\frac{1}{8}$ , reflection over the x axis, up 6 and right 2.

Step 1:

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