Try this solution:
1. m∠A=m∠L; m∠B=m∠M and m∠C=m∠N;
2. m∠B=m∠M=35° and m∠C=m∠N=95°;
3. m∠A=m∠L=180°-(m∠B+m∠C)=180-35-95=50°
answer: 50°
Answer:
Step-by-step explanation:
21(5m - 3) = 63*9
105m - 63 = 567
105m = 630
m = 6
Answer:
X= 32 Y= 35
Step-by-step explanation:
We know FOB is parralel to AOE meaning x= 32
also, COH = 90 so GOD is also 90.
a straight angle is 180, so
23+90+x or 32= 145,
180-145=35,
y=35
Answer:true
Step-by-step explanation:
The top line segment (12) is twice as long as the original, smaller (6), segment
This is a typical radioactive decay problem which uses the general form:
A = A0e^(-kt)
So, in the given equation, A0 = 192 and k = 0.015. We are to find the amount of substance left after t = 55 years. That would be represented by A. The solution is as follows:
A = 192e^(-0.015*55)
<em>A = 84 mg</em>
