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mel-nik [20]
3 years ago
5

you and your friend share a package of candies. You eat twice as many candies as your friend. If there were 36 candies in the ba

g, how many did you eat?
Mathematics
1 answer:
Rus_ich [418]3 years ago
5 0

Answer: you ate 24 and your freind ate 12

Step-by-step explanation: x+2x=36

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The volume of a right cone is 264 π units. if its circumference measures 12 π units, find its height
abruzzese [7]

Answer:

r = \frac{12\pi }{\pi } / 2 = 6

volume = 1/3 * π * r² * h

h = 3 * V/π * r^{2}

h = \frac{3 * 264\pi }{\pi  * 6^{2} } = 22

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2 years ago
What is the slope in this equation y=10+3x​
Ghella [55]

Answer:

the slope is 3

Step-by-step explanation:

4 0
3 years ago
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For which equation would x = 5 be a solution?
mars1129 [50]

Answer:

45 ÷ x = 9   ...   45 ÷ 5 = 9

Step-by-step explanation:

5 + 4 ≠ 54

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8 0
3 years ago
You are a lifeguard and spot a drowning child 60 meters along the shore and 40 meters from the shore to the child. You run along
sukhopar [10]

Answer:

The lifeguard should run across the shore a distance of 48.074 m before jumpng into the water in order to minimize the time to reach the child.

Step-by-step explanation:

This is a problem of optimization.

We have to minimize the time it takes for the lifeguard to reach the child.

The time can be calculated by dividing the distance by the speed for each section.

The distance in the shore and in the water depends on when the lifeguard gets in the water. We use the variable x to model this, as seen in the picture attached.

Then, the distance in the shore is d_b=x and the distance swimming can be calculated using the Pithagorean theorem:

d_s^2=(60-x)^2+40^2=60^2-120x+x^2+40^2=x^2-120x+5200\\\\d_s=\sqrt{x^2-120x+5200}

Then, the time (speed divided by distance) is:

t=d_b/v_b+d_s/v_s\\\\t=x/4+\sqrt{x^2-120x+5200}/1.1

To optimize this function we have to derive and equal to zero:

\dfrac{dt}{dx}=\dfrac{1}{4}+\dfrac{1}{1.1}(\dfrac{1}{2})\dfrac{2x-120}{\sqrt{x^2-120x+5200}} \\\\\\\dfrac{dt}{dx}=\dfrac{1}{4} +\dfrac{1}{1.1} \dfrac{x-60}{\sqrt{x^2-120x+5200}} =0\\\\\\  \dfrac{x-60}{\sqrt{x^2-120x+5200}} =\dfrac{1.1}{4}=\dfrac{2}{7}\\\\\\ x-60=\dfrac{2}{7}\sqrt{x^2-120x+5200}\\\\\\(x-60)^2=\dfrac{2^2}{7^2}(x^2-120x+5200)\\\\\\(x-60)^2=\dfrac{4}{49}[(x-60)^2+40^2]\\\\\\(1-4/49)(x-60)^2=4*40^2/49=6400/49\\\\(45/49)(x-60)^2=6400/49\\\\45(x-60)^2=6400\\\\

x

As d_b=x, the lifeguard should run across the shore a distance of 48.074 m before jumpng into the water in order to minimize the time to reach the child.

7 0
3 years ago
Can someone please help me
xenn [34]
It’s y = (x + 1) ^2 - 9
4 0
2 years ago
Read 2 more answers
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