Answer:
look below
Step-by-step explanation:
y = 2 (x + 3)^2 - 2
Geometric figure: parabola
Alternate forms:
y = 2 (x + 2) (x + 4)
y = 2 (x^2 + 6 x + 8)
-2 x^2 - 12 x + y - 16 = 0
Expanded form:
y = 2 x^2 + 12 x + 16
Roots:
x = -4
x = -2
<u>Properties as a real function:
</u>
Domain
- R (all real numbers)
Range
- {y element R : y>=-2}
Partial derivatives:
d/dx(2 (x + 3)^2 - 2) = 4 (x + 3)
d/dy(2 (x + 3)^2 - 2) = 0
Implicit derivatives:
(dx(y))/(dy) = 1/(12 + 4 x)
(dy(x))/(dx) = 4 (3 + x)
Global minimum:
min{2 (x + 3)^2 - 2} = -2 at x = -3
Answer:
1 2/3
Step-by-step explanation:
well first reduce it which would be 5/3 since the greatest common denominator would be 4. Then put 3 in the 5 which goes only once and 2 is left over. Keep the threeas the denominator instead of the numerator.
An adult with a weight of 75 kilograms have an <em>equivalent</em> weight of 165.60 pounds.
<h3>How to convert kilograms to pounds</h3>
Herein we have an application of <em>unit</em> conversions between <em>weight</em> units, from kilograms to pounds. Unit conversions follow this <em>direct proportional</em> formula:
y = k · x
Where:
x - Weight in kilograms
y - Weight in pounds
k - Conversion ratio
If we know that x = 75 kg and k = 2.208 lb/kg, then the weight of the adult in pounds is:
y = (2.208 lb/kg) · (75 kg)
y = 165.6 lb
An adult with a weight of 75 kilograms have an <em>equivalent</em> weight of 165.60 pounds.
To learn more on weight units: brainly.com/question/18762697
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Answer:
The probability that she wins exactly once before she loses her initial capital is 0.243.
Step-by-step explanation:
The gambler commences with $30, i.e. she played 3 games.
Let <em>X</em> = number of games won by the gambler.
The probability of winning a game is, <em>p</em> = 0.10.
The random variable <em>X</em> follows a Binomial distribution, with probability mass function:
Compute the probability of exactly one winning as follows:
Thus, the probability that she wins exactly once before she loses her initial capital is 0.243.
