The set of two-digit primes is {11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97}
Of that list, the following primes are mirror images of each other
13 and 31
17 and 71
37 and 73
79 and 97
Note: we ignore 11 since 11 flips to 11 which is not distinct from its original
If you're looking for the largest prime of this form, then its 97
If you're looking for the largest gap, then subtract each pair
31-13 = 18
71-17 = 54
73-37 = 36
97-79 = 18
We see that 71 and 17 have the largest gap
The answer is letter d. The Fibonacci Sequence states to add the 2 previous number to get the next number starting with 1. So, 1 + 0=1, 1+1=2, 1+2=3, 2+3=5,3+5=8, 5+8=13, etc....
I added 13+21 to get 34. Then add 21+34 to get 55. Then add 34+55 to get 89.
Answer:
7n-10
Step-by-step explanation:
=(5n-3) - (-2n) -7 [Bracket Opens]
=5n - 3 +2n -7 [- × - = +]
=7n - 10 [ addition]
Answer:
-1/8
Step-by-step explanation:
(-1/2) ^3
(-1/2)(-1/2)(-1/2)
-1/8
