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3 years ago

Divide x4+2x2−24 by x+2

2 answers:

7 0

$\begin{array}{c|c}_{-}\ x^4+2x^2-24 &\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\! \underline{ x+2 } \\ \!\!\!\!\!\!\!\!\!\!\! \underline{x^4+2x^3}& x^3-2x^2+4x-8 \\{ \big{_{-}}}-2x^3-24& \\\underline{-2x^3-4x^2}& \\ _{-} \ 4x^2-24 & \\ \underline{4x^2+8x}& \\ _{-}-8x-24& \\ \underline{-8x-16} & \\ -8 &\end {array }$

$\displaystyle \frac{x^4+2x^2-24}{x+2} =x^3-2x^2+4x-8 -\frac{8}{x+2}$

sweet [91]3 years ago

7 0

Answer:

8/x+2

Step-by-step explanation:

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What is the coefficient of q in the sum of (2/3q-3/4) and(-1/6q-r)?

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The coefficient is $\frac{1}{2}$

Step-by-step explanation:

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$=\frac{2}{3}q -\frac{1}{6}q-\frac{3}{4})-r)$

We collect the LCM for the $q$ terms;

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There are 12 red marbles and 8 green marbles in a bag. What is the probability of selecting a red

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Answer:

The probability of selecting a red marble, not replacing it, and then selecting a green marble from the bag is 24/95

Step-by-step explanation:

Number of red marbles = 12

Number of green marbles = 8

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Probability of selecting red marble = $\frac{12}{20}$

Since it is the case of no replacement

Remaining marbles = 20-1 = 19

Number of red marbles = 12-1=11

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Probability of selecting green marble = $\frac{8}{19}$

So, the probability of selecting a red marble, not replacing it, and then selecting a green marble from the bag = $\frac{12}{20} \times \frac{8}{19}=\frac{24}{95}$

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