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larisa [96]
3 years ago
6

Use properties to evaluate 7/5(1/4 divide 7/4)(-10)

Mathematics
1 answer:
cricket20 [7]3 years ago
3 0
The answer isssssss c -2
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Owen runs 37 miles every 2 weeks. Enter the number of miles Owen runs in 12 weeks
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I think it’s 222 because he runs 18.5 miles every week and 18.5 x 12 = 222
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Emma took 35 pictures of flowers on a nature walk and an additional 3 pictures of each bird she saw. She took a total of 83 pict
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35 + 3x = 83 is the equation
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An item is regularly priced at $35. It is on sale for 20% off the regular price. How much (in dollars) is discounted from the re
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For a normal distribution, is it likely that a data value selected at random is more than 2 standard deviations above the mean?
makkiz [27]

Answer:

P(X>\mu + 2\sigma)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

Using the z score formula we want this probability:

P(Z>2)

And using the complement rule we got:

P(Z>2) = 1-P(Z

And that correspond to only 0.023*100= 2.3%, so is not frequently and the most appropiate answer for this case would be:

No. This event happens only 2.5% of the time

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the variable of interst of a population, and for this case we know the distribution for X is given by:

X \sim N(\mu,\sigma)  

Where \mu the mean and \sigma  the deviation

We are interested on this probability

P(X>\mu + 2\sigma)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

Using the z score formula we want this probability:

P(Z>2)

And using the complement rule we got:

P(Z>2) = 1-P(Z

And that correspond to only 0.023*100= 2.3%, so is not frequently and the most appropiate answer for this case would be:

No. This event happens only 2.5% of the time

8 0
3 years ago
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