Answer:
x=3
Step-by-step explanation:
We have to use the fact that all angles of a triangle add up to 180 and two supplementary angles add up to 180.
First,QRS forms a line, so angle QRT and angle TRS add up to 180 or, if we call angle TRS y for the sake of having it as a variable, 45x+y=180 or y=180-45x
Now we have all three angles of the triangle, and we know all three add up to 180, so startign with our newly found angle, (180-45x)+(25x)+(57+x)=180
180-45x+25x+57+x=180
237 - 19x = 180
57 = 19x
x=3
Let me know if you need any further explanation.
Answer:
j = -1
Step-by-step explanation:
Eliminate parentheses:
-24 -3j = -16 +5j
Add 3j+16
-8 = 8j
Divide by the coefficient of j.
-1 = j
Answer:

where w is width of rectangle.
Step-by-step explanation:
We are given the following in the question:
The perimeter of a rectangle must be less than 170 feet.
Length of rectangle = 44 feet
Perimeter of rectangle =

Let w be the width of rectangle.
According to the question,

Thus, the width of triangle should be less than 41. Since w cannot take negative values, we can express value of w in interval notation as,


so solve for "x", to see how much is the company paying for the purchase of 1 minute
now, they're plan to sell the minute for 8cents, how much is the profit?
that is, the difference from their cost of the cents to the planned selling price.
bear in mind, is 46,000,000 minutes, so whatever value you get for 1minute,
you need to multiply it for 46,000,000 to get the actual cost.
and the revenue from the sell of 8cents per minute, is of course, 8 * 46,000,000
profit = revenue - cost
Answer:
Answer:
safe speed for the larger radius track u= √2 v
Explanation:
The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.
Also given that r_1= smaller radius
r_2= larger radius curve
r_2= 2r_1..............i
let u be the speed of larger radius curve
now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}∑F=
r
1
mv
2
=
r
2
mu
2
................ii
form i and ii we can write
v^2= \frac{1}{2} u^2v
2
=
2
1
u
2
⇒u= √2 v
therefore, safe speed for the larger radius track u= √2 v