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arsen [322]
3 years ago
7

If y varies directly as x, and y is 48 when x is 6, which expression can be used to find the value of y when c is 2?

Mathematics
1 answer:
Anarel [89]3 years ago
7 0
Direct variation has the for y=kx  (inverse variation has the form y=k/x)

Since we are given a point we can solve for the constant of variation, k

48=6k so

k=8 so our equation is:

y=8x so

y(2)=8(2)

y(2)=16

So y=16 when x=2
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If IQ scores are normally distributed with a mean of 100 and a standard deviation of 5, what is the probability that a person se
notsponge [240]

Answer:

2.28% probability that a person selected at random will have an IQ of 110 or higher

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 100, \sigma = 5

What is the probability that a person selected at random will have an IQ of 110 or higher?

This is 1 subtracted by the pvalue of Z when X = 110. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{110 - 100}{5}

Z = 2

Z = 2 has a pvalue of 0.0228

2.28% probability that a person selected at random will have an IQ of 110 or higher

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mrs_skeptik [129]

Answer:

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