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3 years ago

Determine all values of the constant A so that function of all values of x are continuous

Mathematics

1 answer:

Elden [556K]3 years ago

3 0

Answer:

A function being continuous at a point means that the two-sided limit at that point exists and is equal to the function's value.

Step-by-step explanation:

Point/removable discontinuity is when the two-sided limit exists, but isn't equal to the function's value. hope this helps you :)

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Point B is at (4,-16).Where is B prime after a dilation with a scale factor of 3/4

torisob [31]

(4,-16) factor 3/4
3/4 ×4=3 , -16×3/4= -12
B' (3,-12)

5 0

3 years ago

1 - Qual a solução da equação 3x – 4 = 14? * 1 ponto a) 10 b) 7 c) 6 d) 15 2 - A idade de um pai é igual ao triplo da idade do f

topjm [15]

Responda:

1.) 6;

2.) d) O pai tem 36 anos e o filho tem 12 anos.

Explicação passo a passo:

1.)

Dada a equação: 3x - 4 = 14

3x = 14 + 4

3x = 18

Divida os dois lados por 3

x = 6

2) Dado que ;

Idade do pai = 3 vezes a idade do filho

Idade do pai + idade do filho = 48

Deixe a idade do pai = f; idade da criança = c

Matematicamente ;

f = 3c - - - (1)

f + c = 48 - - - - (2)

Substitua f = 3c em (2)

3c + c = 48

4c = 48

c = 48/4

c = 12

Substitua c = 12 em (2)

f + 12 = 48

f = 48 - 12

f = 36

Portanto ;

Idade do pai = 36 Idade da criança = 12

3 0

3 years ago

Can someone pls help me with diagram 2 I'm confused about how I'm supposed to find the number for the corners like the other two

olga_2 [115]

Isn't that interesting? What a neat little problem.

The middle number between a and b = (a + b)/2
The middle number between b and c = (b + c) / 2
The middle number between c and d = (c + d)/2
The middle number between d and a = (d + a)/2

The sum of the numbers in the corners of
diagram 1 = a + b + c + d Do you agree.

Now look at diagram two. Start by putting a, b, c and d in the corners.
Now remove the brackets from what I found above.
diagram 2 = a/2 + b/2 + b/2 + c/2 + c/2 + d/2 + d/2 + a/2 Now collect all the like terms.
diagram 2 = a/2 + a/2 + b/2 + b/2 + c/2 + c/2 + d/2 + d/2
a/2 + a/2 = a does it not?
b/2 + b/2 = b
c/2 + c/2 = c
d/2 + d/2 = d

The sum of the middle numbers in diagram 2 = a + b + c + d
But that's the same sum as diagram 1, which was what you were asked to prove. You cannot come up with a counter example that will give a different result, at least in the positive integers.

The question provides you with room for a written answer. You are going to have to reproduce in some form what I've put in italics.

Thank you for posting.

6 0

3 years ago

Blake gives piano lessons in the evenings.

Aliun [14]

Answer:

The correct answer is B. {0, 20, 40, 60, 80, 100, 120}

Step-by-step explanation:

1. Let's check all the information given to answer this question correctly:

Rate of each piano lesson Blake gives = US$ 20

Blake can give between 0 and 6 lessons every evening

Earnings = Number of lessons * Rate of each lesson

2. What is the range of this relation?

Let's recall that the domain of a relation is the set of all values for which the relation is defined, and the range of the relation is the set of all values that the relation takes.

It means that the domain of the relation in this case is the number of lessons that Blake can give every evening:

{0, 1, 2, 3, 4, 5, 6}

And the range of this relation is the amount Blake earns in an evening depending on the number of lessons he gives:

{0, 20, 40, 60, 80, 100, 120}

The correct answer is B. {0, 20, 40, 60, 80, 100, 120}

3 0

3 years ago

Read 2 more answers

To qualify for Gold status at Awesome Airlines, one must fly less than 39600 but at least 14400 miles each year. If Elliot takes

nata0808 [166]

Step-by-step explanation:

Below is an attachment containing the solution.