Given:
15 students
2 students must be chosen.
No repetition, no order
This is a combinations problem. We use this formula: n! / (n-r)!(r!)
n = 15 ; r = 2
15! / (15-2)!(r!) ⇒ 15! / 13! * 2! = 105
Z score=(data value-mean)/standard deviation
z=(90-100)/15=-0.6666666667
Given triangle ABC with coordinates A(−6, 4), B(−6, 1), and C(−8, 0), and its image A′B′C′ with A′(−2, 0), B′(−5, 0), and C′(−6,
Zinaida [17]
Answer:
The line of reflection is at y = x+6.
Step-by-step explanation:
The perpendicular bisector of AA' is a line with slope 1 through the midpoint of AA', which is (-4, 2). In point-slope form, the equation is ...
y = 1(x +4) +2
y = x + 6 . . . . . . . line of reflection
Answer:
-74
Step-by-step explanation:
Graph the function. See attached picture. Between the interval where -4 > x < 0, the graph rises up to a peak and descends back down when x = 0. This means the minimum value will be where x = -4.
Substitute x = -4 into the equation.
f(-4) = (-4)^3 -3(-4)^2 - 9(-4) + 2
f(-4) = -64 -3(16) +36 + 2
f(-4) = -64 - 48 + 36 + 2
f(-4) = -74
