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tigry1 [53]
3 years ago
14

Circle O is shown. 2 secants intersect at a point outside of the circle to form angle 1. The first arc formed is d, and the seco

nd arc formed is b. Arcs a and c are the other 2 arcs outside of the secants.
Which equation is correct regarding the measure of ∠1?

m∠1 = One-half(a – c)
m∠1 = One-half(a + c)
m∠1 = One-half(b – d)
m∠1 = One-half(b + d)
Mathematics
2 answers:
Crank3 years ago
7 0

Answer:

C    i think you have to use the formula    hope this helps!   :)

Step-by-step explanation:

Circle O is shown. 2 secants intersect at a point outside of the circle to form angle 1. The first arc formed is d, and the second arc formed is b. Arcs a and c are the other 2 arcs outside of the secants.

Which equation is correct regarding the measure of ∠1?

m∠1 = One-half(a – c)

m∠1 = One-half(a + c)

m∠1 = One-half(b – d)

m∠1 = One-half(b + d)

charle [14.2K]3 years ago
6 0

Answer:

C

Step-by-step explanation:

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Solve the compound inequality 6b < 36 or 2b + 12 > 6.
Ne4ueva [31]

The solution to the compound inequality given as 6b < 36 or 2b + 12 > 6 is b < 6 or b > -3

<h3>How to solve the compound inequality?</h3>

The compound inequality is given as:

6b < 36 or 2b + 12 > 6

Evaluate the like terms in the individual inequalities

6b < 36 or 2b > -6

Divide the individual inequalities by the coefficients of b

b < 6 or b > -3

Hence, the solution to the compound inequality given as 6b < 36 or 2b + 12 > 6 is b < 6 or b > -3

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1 year ago
Determine the center and radius of the following circle equation:
ycow [4]
Center: (6, -6)
Radius: 7
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3 years ago
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Step-by-step explanation:

7 0
3 years ago
Suppose a random sample of size is selected from a population with . Find the value of the standard error of the mean in each of
77julia77 [94]

Answer:

A) σ_x' = 1.4142

B) σ_x' = 1.4135

C) σ_x' = 1.4073

D) σ_x' = 1.343

Step-by-step explanation:

We are given;

σ = 10

n = 50

A) when size is infinite, the standard deviation of the sample mean is given by the formula;

σ_x' = σ/√n

Thus,

σ_x' = 10/√50

σ_x' = 1.4142

B) size is given, thus, the standard deviation of the sample mean is given by the formula;

σ_x' = (σ/√n)√((N - n)/(N - 1))

Thus, with size of N = 50,000, we have;

σ_x' = 1.4142 x √((50000 - 50)/(50000 - 1))

σ_x' = 1.4142 x 0.9995

σ_x' = 1.4135

C) at N = 5000;

σ_x' = 1.4142 x √((5000 - 50)/(5000 - 1))

σ_x' = 1.4073

D) at N = 500;

σ_x' = 1.4142 x √((500 - 50)/(500 - 1))

σ_x' = 1.343

3 0
3 years ago
Rationalize the numerator of the expression
dangina [55]
Multiply by the conjugate for the numerator
3 0
3 years ago
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