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tigry1 [53]
3 years ago
14

Circle O is shown. 2 secants intersect at a point outside of the circle to form angle 1. The first arc formed is d, and the seco

nd arc formed is b. Arcs a and c are the other 2 arcs outside of the secants.
Which equation is correct regarding the measure of ∠1?

m∠1 = One-half(a – c)
m∠1 = One-half(a + c)
m∠1 = One-half(b – d)
m∠1 = One-half(b + d)
Mathematics
2 answers:
Crank3 years ago
7 0

Answer:

C    i think you have to use the formula    hope this helps!   :)

Step-by-step explanation:

Circle O is shown. 2 secants intersect at a point outside of the circle to form angle 1. The first arc formed is d, and the second arc formed is b. Arcs a and c are the other 2 arcs outside of the secants.

Which equation is correct regarding the measure of ∠1?

m∠1 = One-half(a – c)

m∠1 = One-half(a + c)

m∠1 = One-half(b – d)

m∠1 = One-half(b + d)

charle [14.2K]3 years ago
6 0

Answer:

C

Step-by-step explanation:

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How to solve these two problems ?
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8)  \theta is -0.896 radians

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Solution:

8)

Given that,

tan\ \theta = \frac{-5}{4}

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From given,

tan\ \theta = \frac{-5}{4}\\\\\theta = tan^{-1} \frac{-5}{4}\\\\\theta = tan^{-1} (-1.25)\\\\\theta = -51.34

Thus value of \theta is -51.34 degrees

Convert degrees to radians

-51.34\ degree = -51.34 \times \frac{ \pi }{180}\ radian\\\\-51.34\ degree = -0.896\ radian

Thus \theta is -0.896 radians

9)

From given,

radius = 15.4 cm

\theta = \frac{13 \pi }{15}

<em><u>The length of arc when angle in radians is:</u></em>

arc\ length = r \times \theta\\\\arc\ length = 15.4 \times \frac{ 13 \pi }{15}\\\\arc\ length = 15.4 \times 2.721\\\\arc\ length = 41.91

Thus length of arc is 41.91 cm

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Step-by-step explanation:

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