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nekit [7.7K]
3 years ago
14

If you get this right I'll call you daddy and senpai (MATH)

Mathematics
1 answer:
Assoli18 [71]3 years ago
5 0

1. 2.6 x 10^-2, 6.2 x 10^-1, 3.5 x 10^2, 1.5 x 10^4

2.6 x 10^-2, 6.2 x 10^-1, 3.5 x 10^2, 1.5 x 10^4

2.6 x 10^-2, 6.2 x 10^-1, 3.5 x 10^2, 1.5 x 10^4

2.6 x 10^-2, 6.2 x 10^-1, 3.5 x 10^2, 10^4, 1.5 x 10^4

2. 6^5

3. 9^9

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Last year Lira earned $12,000 less than her husband Todd. Together they earned $75,000. How much did Lira earn last year?
nexus9112 [7]

Given:

Last year Lira earned $12,000 less than her husband Todd.

Together they earned $75,000.

To find:

The amount earned by Lira in last year.

Solution:

Let x be the amount earned by Lira's husband inn last year.

Last year Lira earned $12,000 less than her husband Todd.

Amount earned by Lira = x-12000

Total amount earned by Lira and her husband = x+(x-12000)

                                                                             = 2x-12000

Together they earned $75,000.

2x-12000=75000

2x=75000+12000

2x=87000

x=\dfrac{87000}{2}

x=43500

Now,

Amount earned by Lira = x-12000

                                       = 43500-12000

                                       = 31500

Therefore, the amount earned by Lira in last year is $31500.

6 0
3 years ago
Can you help me i don’t know the answers
Advocard [28]
1)

An irrational number is a number that a) can't be written as a fraction of two whole numbers AND b) is an infinite decimal without any sort of pattern.

For the first answer choice, clearly \frac{1}{3} does not pass the first criterion so we look at the second choice.

Let's come back to \sqrt{2} and \pi.

\frac{2}{9} doesn't meet our first criterion, and let's skip \sqrt{3} for now.

It is often easier to disprove an irrational number than to prove one. There are a few famous irrationals to know (although there is an infinite number of irrationals). The most common are \sqrt{2},  \pi, e,  \sqrt{3}. For now, it's just helpful to know these and recognize them.

So we can check off \sqrt{2},  \pi and \sqrt{3}.

2) 

For this next question, we know that \sqrt{64} = 8. Clearly this isn't irrational. Likewise, \frac{1}{2} isn't irrational. \frac{16}{4} =  \frac{4}{4} = 1, which is rational, leaving only \frac{ \sqrt{20}}{5} =  \frac{2 \sqrt{5} }{5}. By process of elimination, this is the correct answer. Indeed, \sqrt{5} is an irrational number.

3) This notation means that we have 0.3636363636... and so on, to an infinite number of digits. It is called a repeating decimal.

But it can be written as a fraction because its pattern repeats, unlike for an irrational number.

Let's say x=0.36363636.... Would you agree that 100x=36.36363636...? (We choose to multiply by 100 because there are two decimals that repeat. For 1, choose 10, for 3 choose 1,000, and so on.)

Now, let's subtract x from 100x and solve.

100x=36.36363636\\-x \ \ \ \ \ \ \ -0.36363636\\99x=36\\\\x= \dfrac{36}{99}= \dfrac{4}{11}

Voila!
4 0
3 years ago
Read 2 more answers
Converting Explicit formula to Recursive formula.
Kruka [31]
The formula
a(n) = 2 - 5(n-1)
is in the form
a(n) = a1 + d(n-1)

where
a1 = first term = 2
d = -5 = common difference

The first term is carried over to the recursive formula. We start with a1 = 2. The next term after that is found by subtracting 5 from the previous term. So
second term = (first term) - 5
third term = (second term) - 5
and so on

The recursive step would be 
a(n) = a(n-1)-5

So that's why the answer is choice C
8 0
3 years ago
Given that a function, g, has a domain of -1 ≤ x ≤ 4 and a range of 0 ≤ g(x) ≤ 18 and that g(-1) = 2 and g(2) = 8, select the st
notka56 [123]

Options

  • (A)g(5) = 12
  • (B)g(1) = -2
  • (C)g(2) = 4
  • (D)g(3) = 18

Answer:

(D)g(3) = 18

Step-by-step explanation:

Given that the function, g, has a domain of -1 ≤ x ≤ 4 and a range of                       0 ≤ g(x) ≤ 18 and that g(-1) = 2 and g(2) = 8

Then the following properties must hold

  1. The value(s) of x must be between -1 and 4
  2. The values of g(x) must be between 0 and 18.
  3. g(-1)=2
  4. g(2)=9

We consider the options and state why they are true or otherwise.

<u>Option A: g(5)=12</u>

The value of x=5. This contradicts property 1 stated above. Therefore, it is not true.

<u>Option B: g(1) = -2 </u>

The value of g(x)=-2. This contradicts property 2 stated above. Therefore, it is not true.

<u>Option C: g(2) = 4 </u>

The value of g(2)=4. However by property 4 stated above, g(2)=9. Therefore, it is not true.

<u>Option D: g(3) = 18</u>

This statement can be true as its domain is in between -1 and 4 and its range is in between 0 and 18.

Therefore, Option D could be true.

3 0
4 years ago
What is the range of 17, 12, 28, 21, 14, 74, 32, 14, 25, 23
natita [175]

Answer:

it's 22 I hope you got it right if not then i'm sorry

8 0
3 years ago
Read 2 more answers
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