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MArishka [77]
4 years ago
7

Converting Explicit formula to Recursive formula.

Mathematics
1 answer:
Kruka [31]4 years ago
8 0
The formula
a(n) = 2 - 5(n-1)
is in the form
a(n) = a1 + d(n-1)

where
a1 = first term = 2
d = -5 = common difference

The first term is carried over to the recursive formula. We start with a1 = 2. The next term after that is found by subtracting 5 from the previous term. So
second term = (first term) - 5
third term = (second term) - 5
and so on

The recursive step would be 
a(n) = a(n-1)-5

So that's why the answer is choice C
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PLEASE HELP :DDDDDDDDDD
Maslowich
Ok start off by finding the base first and the equation of finding the area of the square is A=bh
A=11 x 11= 121 cm^2

Next find the area of one triangle and the equation is A=1/2bh
A=1/2(11)(10)
A=55 cm^2

Multiply the area of one triangle by 4 since there are four triangles and it should equal to 220 cm^2. You then add this to the base and the final answer should be 341 cm^2.

I hope this helps
6 0
3 years ago
Read 2 more answers
Which algebraic expression is equivalent to the expression below?
natka813 [3]
Simple....

you have 7(5x+3)+3(12-x)....

just take them apart....

7(5x+3)

distribute the 7...

7*5x=35x
and
7*3=21

Now, the other part...

3(12-x)

Distribute the 3...

3*12=36
and
3*-x=-3x   

Now, add what you have found....

35x+21+36-3x

32x+57

Thus, your answer, A.                                                                                            
8 0
4 years ago
21) Which expression is equivalent to 6(7x − 4)? A) 13x − 10 B) 13x − 24 C) 42x − 10 D) 42x − 24
Sergio039 [100]

Answer:

Answer is D) 42x − 24

Step-by-step explanation:

Opening the expression given in question

6(7x − 4)

6 will be multiplied by both items present inside parenthesis.

it can be written as

={(6 * 7x) - (6*4)}

=42x-24

Hope that clears the question.

7 0
3 years ago
Anyone? please help asap i really want to finish this
yan [13]

Q. 3

b \geqslant 2 \\

<u>b∈(2,∞)</u>

Q. 4

r   <  - 5

<u>r∈(-∞, -5)</u>

5 0
2 years ago
Given g(x) = <img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7Bx%5E2%2B2x%7D" id="TexFormula1" title="\frac{3}{x^2+2x}" alt="\f
sweet [91]

We know that g(x) = \frac{3}{x^2+2x}

We have to find g^-1(x)  or inverse of g(x)

Inverse of g(x) can be determined by equating g(x) to y, and determining the value of x in terms of y

g(x) = y = \frac{3}{x^2+2x}

⇒ y × (x² + 2x) = 3

⇒ yx² + 2xy = 3

⇒ yx² + 2yx - 3 = 0

Determining the roots of x using:

x = \frac{-b + \sqrt{b^{2} - 4ac}}{2a} OR x = \frac{-b - \sqrt{b^{2} - 4ac}}{2a} , where a is coefficient of x², b is coefficient of x, and c is the constant

⇒ x = \frac{-2y + \sqrt{4y^2 - 4(2y)(-3)}}{2y} OR x = \frac{-2y - \sqrt{4y^2 - 4(2y)(-3)}}{2y}

⇒ x = \frac{-2y + \sqrt{4y^2 + 24y}}{2y} OR x = \frac{-2y - \sqrt{4y^2 + 24y}}{2y}

Hence, g^-1(x) = \frac{-2y + \sqrt{4y^2 + 24y}}{2y} OR x = \frac{-2y - \sqrt{4y^2 + 24y}}{2y}

7 0
4 years ago
Read 2 more answers
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