2 years ago

If f(c)=2x^2-x, find f(-4) - f(9)

Mathematics

1 answer:

murzikaleks [220]2 years ago

7 0

Answer:

-13f

Simplify by combining the sum of 4 + 9 with the term "f" and assume integers will be negative.

You might be interested in

Evaluate the expression solve for y = 1<br><br> -11.8 + 33.4y

gladu [14]

-11.8 + 33.4y
First turn y into 1
-11.8 + 33.4 (1)
Multiply 1 by 33.4
-11.8 + 33.4
Then add
21.6
Hope this helps!!

3 0

2 years ago

Read 2 more answers

I GOT STUCK ON THIS QUESTION ON MY MATH TEST SO .. PLS HELP ME <3

HACTEHA [7]

Answer:

x x x c. c c c c d sbsbbdbcbdbcbbxbcbcbbvbbcbvbcbcbcnc

3 0

2 years ago

Find the Maclaurin series for f(x) using the definition of a Maclaurin series. [Assume that f has a power series expansion. Do n

Mazyrski [523]

We can use the fact that, for $|x|$ ,

$\displaystyle\frac1{1-x}=\sum_{n=0}^\infty x^n$

Notice that

$\dfrac{\mathrm d}{\mathrm dx}\left[\dfrac1{1-x}\right]=\dfrac1{(1-x)^2}$

so that

$f(x)=\displaystyle\frac5{(1-x)^2}=5\frac{\mathrm d}{\mathrm dx}\left[\sum_{n=0}^\infty x^n\right]$

$f(x)=\displaystyle5\sum_{n=0}^\infty nx^{n-1}$

$f(x)=\displaystyle5\sum_{n=1}^\infty nx^{n-1}$

$f(x)=\displaystyle5\sum_{n=0}^\infty(n+1)x^n$

By the ratio test, this series converges if

$\displaystyle\lim_{n\to\infty}\left|\frac{(n+2)x^{n+1}}{(n+1)x^n}\right|=|x|\lim_{n\to\infty}\frac{n+2}{n+1}=|x|$

so the series has radius of convergence $R=1$ .

5 0

2 years ago

Help me with this now please

otez555 [7]

Step-by-step explanation:

davis is right.

5 0

2 years ago

Use one or more properties to rewrite the expression as an equivalent expression that does not use parenthesis. (5+10p)+13. A. 2

bulgar [2K]

It will be D. because you have to add the like terms which is 13 + 5 which will be 18 and so 10p doesn't have no like terms it just stays the same so it will be 10p+18

7 0

2 years ago