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2 years ago

If f(c)=2x^2-x, find f(-4) - f(9)

Mathematics

1 answer:

murzikaleks [220]2 years ago

7 0

Answer:

-13f

Simplify by combining the sum of 4 + 9 with the term "f" and assume integers will be negative.

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Amy has 120 acres of peanuts. She risked the soil using a 16-foot disk traveling 4.2 miles per hour.she used 0.62 gallon per acr

lesya [120]

Where is the question?????

3 0

3 years ago

Evaluate n+2x2 when n=3 and x=−2.

krok68 [10]

Answer:

When n=3 and x=−2 the answer is 11.

Step-by-step explanation:

Given:

Let p (n,x) be the function such that

$p (n,x) = n + 2x^{2}$

To Find:

p (n,x) = p ( 3, -2) = ?

Solution:

$p (n,x) = n + 2x^{2}$

Substituting n = 3 and x = -2 we get

$p (3, -2) = 3 + 2(-2)^{2}$

Negative square gives positive number therefore (-2)²=4

$p (3, -2) = 3 + 2\times 4$

$p (3, -2) = 3 + 8\\p (3, -2) = 11$

When n=3 and x=−2 the answer is 11.

7 0

3 years ago

Write an algebraic expression that represent the sum of 8 and two-third of x?

lesantik [10]

We have to sum 8 and two-third of x, so we must multiply x by 2/3 and sum it with 8,

thus, the expression is

$\frac{2}{3}x+8$

3 0

1 year ago

Is 10/3 equivalent to 70/21

slava [35]

Yes because if you divide both, the numerator and denominator, by 7 it would simplify to 10/3, so they are equivalent.

7 0

3 years ago

For which rational expression is 8 an excluded value ? check all that apply

denis23 [38]

<u>Answer:</u>

The correct answer options are C. $\frac{x^2+5}{x-8}$ and D. $\frac{x^2-x-56}{x^2-64}$ .

<u>Step-by-step explanation:</u>

The values which make the denominator equal to zero are called the excluded values.

Here, we can substitute 8 for x and check if it makes the denominator 0.

$\frac{x-8}{x+8} = \frac{8-8}{8+8} =\frac{0}{16} =0$

$\frac{x-2}{x^2-4} = \frac{8-2}{8^2-4} =\frac{6}{60} =\frac{1}{10}$

$\frac{x^2+5}{x-8} = \frac{8^2+5}{8-8} =\frac{69}{0}$

$\frac{x^2-x-56}{x^2-64} = \frac{8^2-8-56}{8^2-64} = \frac{0}{0} =0$

$\frac{8x^2-2}{x^2-16} = \frac{8(8)^2-2}{8^2-16} =\frac{510}{48}$

7 0

3 years ago