Which equation of a line contains point (1-1) and is parallel toy = 2x + 5?

Mathematics

1 answer:

ella [17]2 years ago

8 0

Answer:

Answer is y = 2x - 3

Step-by-step explanation:

• Equation of parallel lines have the same slope. So first two equations are okay.

• For point (1, -1):

${ \rm{y = mx + c}} \\ { \rm{ - 1 = 2 + c}} \\ { \rm{c = - 3}}$

• Equation is y = 2x - 3

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2 years ago

Solve 2(b − 3) ≥ 3(3 − b) and describe the graph of the solution. Show all your work.

solong [7]

Answer:

$\large\boxed{b\geq3\to b\in[3,\ \infty)}$

Step-by-step explanation:

$2(b-3)\geq3(3-b)\qquad\text{use the distributive property:}\ a(b+c)=ab+ac\\\\(2)(b)+(2)(-3)\geq(3)(3)+(3)(-b)\\\\2b-6\geq9-3b\qquad\text{add 6 to both sides}\\\\2b-6+6\geq9+6-3b\\\\2b\geq15-3b\qquad\text{add}\ 3b\ \text{to both sides}\\\\2b+3b\geq15-3b+3b\\\\5b\geq15\qquad\text{divide both sides by 5}\\\\\dfrac{5b}{5}\geq\dfrac{15}{5}\\\\b\geq3$