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2 years ago

5

The length of a rectangular field is 7 m less than 4 times the width. The perimeter is 136 m. Find the width and the length

1 answer:

Helga [31]2 years ago

6 0

Answer:

Step-by-step explanation:

Represent the width by W. Then, "The length of a rectangular field is 7 m less than 4 times the width" expressed symbolically is

L = 4W - 7 (dimensions in meters)

Recall that the perimeter formula in this case is P = 2L + 2W, and recognize that the perimeter value is 136 m. After substituting 4W - 7 for L, we get:

136 m = 2(4W - 7) + 2W, or

136 = 8W - 14 + 2W, or

150 = 10W These three equations are equivalent mathematical statements.

150 = 10W reduces to W = 15 (meters).

Part A: the independent variable is W, the width of the field.

Part B: The mathematical statement is 136 m = 2(4W - 7) + 2W, which after algebraic manipulation becomes 150 = 10W.

Part C: The above equation can be solved for W: W = 15 meters. This is the value of the independent variable.

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2 years ago

Find limit as x approaches two of quantity x squared minus four divided by quantity x minus two. You must show your work or expl

Brut [27]

Answer:

4

Step-by-step explanation:

lim (x^2 - 4) / (x - 2)

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When we plug x =2, we get

(2^2 - 4) / (2 - 2)

= (4 - 4)/(2 - 2)

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3 0

3 years ago

Read 2 more answers

AveGali [126]

Answer:

Total time taken by walking, running and cycling = 22 minutes.

Step-by-step explanation:

Let the speed of walking = x

As given,

The distance of walking = 1

Now,

As $Time = \frac{Distance }{Speed}$

⇒ Time traveled by walking = $\frac{1}{x}$

Now,

Given that - He runs twice as fast as he walks

⇒Speed of running = 2x

Also given distance traveled by running = 1

Time traveled by running = $\frac{1}{2x}$

Now,

Given that - he cycles one and a half times as fast as he runs.

⇒Speed of cycling = $\frac{3}{2}$ (2x) = 3x

Also given distance traveled by cycling = 1

Time traveled by cycling = $\frac{1}{3x}$

Now,

Total time traveled = Time traveled by walking + running + cycling

= $\frac{1}{x}$ + $\frac{1}{2x}$ + $\frac{1}{3x}$

= $\frac{6+3+2}{6x} = \frac{11}{6x}$

If he cycled the three mile , then total time taken = $\frac{1}{3x}$ + $\frac{1}{3x}$ + $\frac{1}{3x}$ = x

Given,

He takes ten minutes longer than he would do if he cycled the three miles

⇒x + 10 = $\frac{11}{6} x$

⇒ $x - \frac{11}{6} x = -10$

⇒ $-\frac{5}{6}x = -10$

⇒x = $\frac{60}{5}$ = 12

⇒x = 12

∴ we get

Total time traveled by walking + running + cycling = $\frac{11}{6} x = \frac{11}{6} (12) = 11 (2) = 22$ min

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2 years ago

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2 years ago

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