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4 years ago

Please someone Answer!!!!!

Physics

2 answers:

Mkey [24]4 years ago

8 0

Answer:

Explanation:

The expression which represents electric potential energy is given by

$U_{E}(r)=k_{e}{\frac{qQ}{r}}$

Where q and Q are the charges in the balloons

r = Distance between the charges or balloons

k = Coulomb's constant

It can be seen that the potential energy varies inversely with distance. This means that if the distance decreases the potential energy will increase.

In case B the distance between the balloons is the lowest so the electric potential energy will be maximum.

joja [24]4 years ago

7 0

It's B lol they are being forced apart but can't move because the are tied down

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If a charge at 60c flow in a conductor for 30 second then the current that flow in a conductor is

saw5 [17]

Explanation:

<h3>Given</h3>

- Charge = 60c

time = 30 sec

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Current = Charge/time

I = V/T

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3 0

3 years ago

Three wires meet at a junction. Wire 1 has a current of 0.40 A into the junction. The current of wire 2 is 0.57 A out of the jun

AlekseyPX

Answer:

a. 1.56 × 10¹⁸ electrons per second

b. The electrons in wire 3 flow into the junction.

Explanation:

Here is the complete question

Three wires meet at a junction. Wire 1 has a current of 0.40 A into the junction. The current of wire 2 is 0.65 A out of the junction. (a) How many electrons per second move past a point in wire 3? (b) In which direction do the electrons move in wire 3 -- into or out of the junction?

Solution

(a) How many electrons per second move past a point in wire 3?

Using Kirchhoff's current law, at the junction, i₁ + i₂ + i₃ = 0 where i₁ = current in wire 1 = 0.40 A, i₂ = current in wire 2 = 0.65 A and i₃ = = current in wire 3,

So, i₃ = -(i₁ + i₂)

taking current flowing into the junction as positive and those leaving as negative, i₁ = + 0.40 A and i₂ = -0.65 A

So, i₃ = -(i₁ + i₂)

i₃ = -(0.40 A + (-0.65 A))

i₃ = -(0.40 A - 0.65 A)

i₃ = -(-0.25 A)

i₃ = 0.25 A

Since i₃ = 0.25 C/s and we have e = 1.602 × 10⁻¹⁹ C per electron, then the number of electrons flowing in wire 3 per second is i₃/e = 0.25 C/s ÷ 1.602 × 10⁻¹⁹ C per electron = 0.1561 × 10¹⁹ electrons per second = 1.561 × 10¹⁸ electrons per second ≅ 1.56 × 10¹⁸ electrons per second

(b) In which direction do the electrons move -- into or out of the junction?

Given that i₃ = + 0.25 A and that positive flows into the junction, thus, the electrons in wire 3 flow into the junction.

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3 years ago

If a flea can jump straight up to a height of 0.410 m , what is its initial speed as it leaves the ground?

aivan3 [116]

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$\(0^2 = {v_0}^{2} - 2 \times 9.8 \times 0.410$

${v_0}^{2} = 2 \times 9.8 \times 0.410$

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Dvinal [7]

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hope this ans may help you.

thankyou

Mrk me brainilist

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3 years ago