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Pie
3 years ago
10

6 cm object is 15 cm from a convex lens that has a focal length of 5 cm. What is the distance of the image from the lens, to the

nearest hundredth?
Physics
2 answers:
Agata [3.3K]3 years ago
7 0
The distance of the image from the lens is 7.5 (7.5 = 1 / (1/5-1/15) cm. This problem can be solved using the converging lens formula for the distance which is the 1/f = 1/do + 1/di formula where f is the focal length, do is the object's distance to the lens, and di is the image's distance from the lens.
shusha [124]3 years ago
5 0

Answer:

Image will form at distance 7.5 cm from lens

Explanation:

As we know by the lens formula

\frac{1}{d_i} + \frac{1}{d_0} = \frac{1}{f}

here we know that

d_i = 15 cm

f = 5 cm

now we have

\frac{1}{15} + \frac{1}{d_i} = \frac{1}{5}

d_i = 7.5 cm

so here a real image will form on the other side of lens at distance 7.5 cm

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A monochromatic light falls on two narrow slits that are 4.50 um apart. The third destructive fringes which are 35° apart were f
STatiana [176]

Answer:

 y = 1.19 m  and λ = 8.6036 10⁻⁷ m

Explanation:

This is a slit interference problem, the expression for destructive interference is

          d sin θ = m λ

indicate that for the angle of θ = 35º it is in the third order m = 3 and the separation of the slits is d = 4.50 10⁻⁶ m

          λ = d sin  θ / m

let's calculate

          λ = 4.50 10⁻⁶ sin 35  /3

          λ = 8.6036 10⁻⁷ m

for the separation distance from the central stripe, we use trigonometry

         tan θ= y / L

         y = L tan θ

the distance L is measured from the slits, it indicates that the light source is at x = 0.30 m from the slits

         L = 2 -0.30

         L = 1.70 m

           

let's calculate

        y = 1.70 tan 35

        y = 1.19 m

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Explanation:

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