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3 years ago

Please help me what is the value of x+y

Mathematics

2 answers:

Norma-Jean [14]3 years ago

7 0

The correct answer ic C)12

djverab [1.8K]3 years ago

6 0

Your answer is c, 12. The triangle is based on the ratio 1:2, so we know that the values for ΔV must be 2·(any given side). Thus, x=4 and y=8, so x+y=12. Hope this helps!

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Log3 (x squared + 7x + 21) = 2

Nezavi [6.7K]

Step-by-step explanation:

log <base a> b = x

means

a^x = b

3^2 = x^2+7x+21

x^2 + 7x + 21 - 9 = 0

x^2 + 7x + 12 = 0

(x+3)(x+4)

x = -3 or -4

3 0

3 years ago

Solve for A R=x(A+B)

julia-pushkina [17]

R=x(A+B)
divide both sides by x
R/x=A+B
minus B both sides
(R/x)-B=A
A=(R/x)-B

5 0

3 years ago

The sum of reciprocals of rehman’s ages 3 years ago and 5 years from now is 1/3. Find his present age

Afina-wow [57]

Answer:

His age is 7 years.

Step-by-step explanation:

Let Rehman's present age be x years.

1 / (x - 3) + 1 /(x + 5) = 1/3

Multiply through by the LCD 3(x - 3)(x + 5):

3(x + 5) + 3(x - 3) = (x + 5)(x - 3)

3x + 15 + 3x - 9 = x^2 + 2x - 15

x^2 + 2x - 6x - 30 + 9 = 0

x^2 - 4x - 21 = 0

(x - 7)(x + 3) = 0

x = 7 (answer).

6 0

3 years ago

Bilal's favorite colors are red and green.

Arte-miy333 [17]

Answer:

P(A∪B) = 1/3

Step-by-step explanation:

Red Garments = 1 red shirt + 1 red hat + 1 red pairs of pants

Total Red Garments = 3

Green Garments = 1 green shirt + 1 green scarf + 1 green pairs of pants

Total Green Garments = 3

The total number of garments = Total Red Garments + Total Green Garments:

3 + 3 = 6

Let A be the event that he selects a green garment

P(A) = Number of required outcomes/Total number of possible outcomes

P(A) = 3/6

Let B be the event that he chooses a scarf

P(B) = 1/6

The objective here is to determine P(A or B) = P(A∪B)

Using the probability set notation theory:

P(A∪B) = P(A) + P(B) - P(A∩B)

P(A∩B) = Probability that a green pair of pant is chosen = P(A) - P(B)

= 3/6-1/6

= 2/6

P(A∪B) = 1/2 + 1/6 - 2/6

P(A∪B) = 2/6

P(A∪B) = 1/3

8 0

3 years ago

Read 2 more answers

A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 421 gram setting. It is

Anastaziya [24]

Answer:

The p-value is approximately 0.0508

Step-by-step explanation:

The given parameters are;

The expected mass of banana chips bag filled by the machine, μ = 421 gams

The number of bags in the sample of bags filled by the machine, n = 26 bags

The mean mass of the bags in the sample, $\overline x$ = 413 grams

The standard deviation of the mass in the bags, s = 24 grams

The level of significance, α = 0.02

The null hypothesis, H₀; μ = 421 grams

The alternative hypothesis, Hₐ; μ < 421 grams

The test statistic is given as follows;

$t=\dfrac{\bar{x}-\mu }{\dfrac{s}{\sqrt{n}}}$

We get;

$t=\dfrac{413-421 }{\dfrac{24}{\sqrt{26}}} \approx -1.6996731712$

The t-value = -1.6996731712

The degrees of freedom df = n - 1 = 26 - 1 = 25

From an online source, we get the critical-t = 2.166587

The p-value is obtained using an online source as p(t ≤ -1.6996731712) = 0.0508

From the p-value table, we get

0.05 < p < 0.1

3 0

3 years ago