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kotykmax [81]
3 years ago
6

Write an equation in point-slope form for the line through the given point with the given slope.

Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
3 0

Answer: A

Step-by-step explanation:

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Find the value of the following 1.8456×101​
Alex Ar [27]

Answer:

186.4056

Step-by-step explanation:

Used a calculator, this is correct

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The volume would be 2040
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Find the volume of the composite solid. Round your answer to the nearest tenth.​
amm1812

Answer:

Volume of the Figure =825.38m^3

Step-by-step explanation:

Volume of the figure = Volume of the Upper cone+Volume of the lower cone

Volume of a cone = \pi *r^2*\frac{h}{3}

Volume of the Upper Cone with  

height=12m

radius=6m

                       3.14*6*6*\frac{12}{3}

                        =3.14*6*6*4\\\\=3.14*36*4\\\\=3.14*144\\\\=147.14m^3

Volume of the Lower cone with radius=6m and height=18m

                            =3.14*6*6*\frac{18}{3} \\\\=3.14*6*6*6\\\\=3.14*36*6\\\\=3.14*216\\\\=678.24m^3

Volume of the Whole Figure =   147.14+678.24

Volume of the Figure  =825.38m^3

4 0
3 years ago
At the U.S open tennis championship a statistician keeps track of every serve that a player hits during the tournament. The mean
GarryVolchara [31]

Answer:

Step-by-step explanation:

Both 115 and 145 mph are above the mean.  Draw a normal curve and mark these speeds.  115 mph is 1 standard deviation above the mean; 130 would be 2 standard deviations above the mean; and 145 would be 3 s. d. above it.

We need to find the area under the standard normal curve between 115 and 145.  This is equivalent to the area under the standard normal curve between z = 1 and z = 3.

I used my TI-83 Plus calculator's DISTR function "normalcdf(" to calculate this area:  normalcdf(1, 3) = 0.1573.

The area between z = 1 and z = 3 is 0.1573.  In other words, the percentage of serves that were between 115 and 145 mph was 15.73%.

8 0
2 years ago
Can you help me solve this question ?
finlep [7]

Answer:

Can u show the whole question pleade

5 0
2 years ago
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