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kotykmax [81]
3 years ago
6

Write an equation in point-slope form for the line through the given point with the given slope.

Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
3 0

Answer: A

Step-by-step explanation:

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Find the net change in the value of the function between the given inputs. h(t) = t2 + 2; from −5 to 8
pashok25 [27]

Answer:

39

Step-by-step explanation:

Given the function :

h(t) = t² + 2

From t = 5 to t = 8

when, t = 5

h(5) = 5² + 2

h(5) = 25 + 2

h(t) at t = 5 ; equals 27

when, t = 8

h(5) = 8² + 2

h(5) = 64 + 2

h(t) at t = 8 ; equals 66

Net Change :

h(8). - h(5)

66 - 27 = 39

3 0
3 years ago
If a = 7 and b = 11, what is the measure of ∠B? (round to the nearest tenth of a degree) A) 32.5° B) 39.2° C) 50.5° D) 57.5°
Ilia_Sergeevich [38]

Answer:

D) 57.5°

Step-by-step explanation:

As the question is not complete. So, let's suppose it is a right angle triangle then, we can apply Pythagoras theorem to calculate the hypotenuse or the third side.

Pythagoras Theorem = c^{2} = a^{2} + b^{2}

a = 7 and b = 11

a^{2} = 49

b^{2} = 121

Plugging in the values, we will get:

c^{2} = 49 + 121

c^{2} = 170

c = \sqrt{170}

To calculate the unknown angle B, we can use law of sine.

Law of sine = \frac{a}{sinA} = \frac{b}{sinB} = \frac{c}{sinC}

So,

\frac{c}{sinC} = \frac{b}{sinB}

\frac{\sqrt{170} }{sin90} =  \frac{11}{sinB}

Sin90 = 1

sinB = \frac{11}{\sqrt{170} }

B = sin^{-1} (\frac{11}{\sqrt{170} })

B = 57.5°

8 0
3 years ago
Write the equation of the line in fully simplified slope-intercept form.
Anna71 [15]

Answer:

Step-by-step explanation:

slope=(0-3)/(3-0)=-3/3=-1

y intercept=3

eq. of line is y=-x+3

3 0
2 years ago
Can anyone help me? I’m stuck big time.
user100 [1]
The answer is 27 degrees I believe
4 0
3 years ago
read this passage from "the black cat": this hideous murder accomplished, i set myself forthwith, and with entire deliberation,
Lapatulllka [165]

D. The business like tone

(Apex approved)

100%best answer


3 0
4 years ago
Read 2 more answers
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