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3 years ago

Perform the indicated operation. h(n)=n-3 g(n)=-2n² + 2 Find (hºg)(n)

Mathematics

1 answer:

Anni [7]3 years ago

3 0

Step-by-step explanation:

$h(n) = n - 3 \\ g(n) = - 2 {n}^{2} + 2 \\ \\ (h.g)(n) = h(n).g(n) \\ = (n - 3).( - 2 {n}^{2} + 2) \\ = n( - 2 {n}^{2} + 2) - 3( - 2 {n}^{2} + 2) \\ = - 2 {n}^{3} + 2n + 6{n}^{2} - 6 \\ \red{\boxed {\bold{\therefore \: (h.g)(n) = - 2 {n}^{3}+ 6{n}^{2} + 2n - 6}}}$

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Verity's sock drawer contains 9 black socks, 5 white socks, and 6 brown socks. If Verity chooses a sock at random, what is the p

Y_Kistochka [10]

Answer:

14/20.

Step.-by-step explanation:

There are 20 socks in the drawer.

The number which are not brown = 9 + 5 = 14.

So the required probability = 14/20.

3 0

3 years ago

I need help n pls explain

WARRIOR [948]

Answer:

The correct option is C). When it was purchased, the coin was worth $6

Step-by-step explanation:

Given function is f(t)= $6\times2^{t}$

Where t is number of years and f(t) is function showing the value of a rare coin.

A figure of f(t) shows that the graph has time t on the x-axis and f(t) on the y-axis.

Also y-intercept at (0,6)

hence, when time t was zero, the value of a rare coin is 6$

f(t)= $6\times2^{t}$

f(0)= $6\times2^{0}$

f(0)=6

Thus,

The correct option is C). When it was purchased, the coin was worth $6

6 0

3 years ago

A contractor is required by a county planning department to submit one, two, three, four, or five forms (depending on the nature

Westkost [7]

Answer:

(a) The value of k is $\frac{1}{15}$ .

(b) The probability that at most three forms are required is 0.40.

(d) $P(y)=\frac{y^{2}}{50} ;\ y=1, 2, ...5$ is not the pmf of y.

Step-by-step explanation:

The random variable Y is defined as the number of forms required of the next applicant.

The probability mass function is defined as:

$P(y) = \left \{ {{ky};\ for \ y=1,2,...5 \atop {0};\ otherwise} \right$

(a)

The sum of all probabilities of an event is 1.

Use this law to compute the value of k.

$\sum P(y) = 1\\k+2k+3k+4k+5k=1\\15k=1\\k=\frac{1}{15}$

Thus, the value of k is $\frac{1}{15}$ .

(b)

Compute the value of P (Y ≤ 3) as follows:

$P(Y\leq 3)=P(Y=1)+P(Y=2)+P(Y=3)\\=\frac{1}{15}+\frac{2}{15}+ \frac{3}{15}\\=\frac{1+2+3}{15}\\ =\frac{6}{15} \\=0.40$

Thus, the probability that at most three forms are required is 0.40.

(c)

Compute the value of P (2 ≤ Y ≤ 4) as follows:

$P(2\leq Y\leq 4)=P(Y=2)+P(Y=3)+P(Y=4)\\=\frac{2}{15}+\frac{3}{15}+\frac{4}{15}\\ =\frac{2+3+4}{15}\\ =\frac{9}{15} \\=0.60$

Thus, the probability that between two and four forms (inclusive) are required is 0.60.

(d)

Now, for $P(y)=\frac{y^{2}}{50} ;\ y=1, 2, ...5$ to be the pmf of Y it has to satisfy the conditions:

$P(y)=\frac{y^{2}}{50}>0;\ for\ all\ values\ of\ y \\$
$\sum P(y)=1$

Check condition 1:

$y=1:\ P(y)=\frac{y^{2}}{50}=\frac{1}{50}=0.02>0\\y=2:\ P(y)=\frac{y^{2}}{50}=\frac{4}{50}=0.08>0 \\y=3:\ P(y)=\frac{y^{2}}{50}=\frac{9}{50}=0.18>0\\y=4:\ P(y)=\frac{y^{2}}{50}=\frac{16}{50}=0.32>0 \\y=5:\ P(y)=\frac{y^{2}}{50}=\frac{25}{50}=0.50>0$

Condition 1 is fulfilled.

Check condition 2:

$\sum P(y)=0.02+0.08+0.18+0.32+0.50=1.1>1$

Condition 2 is not satisfied.

Thus, $P(y)=\frac{y^{2}}{50} ;\ y=1, 2, ...5$ is not the pmf of y.

7 0

3 years ago

Hey can someone help?

Ronch [10]

The value of the given variable x in the missing angles is; x = 12°

<h3>How to find alternate Angles?</h3>

Alternate angles are defined as the angles that occur on opposite sides of the transversal line and as such have the same size. There are two different types of alternate angles namely alternate interior angles as well as alternate exterior angles.

Now, from the question, we can see that ∠4 and ∠6 suit the definition of alternate angles and as such we can say that they are both congruent.

Since ∠4 = (8x + 4)° and ∠6 = (6x + 28)°, then we can say that;

(8x + 4)° = (6x + 28)°

Rearranging this gives us;

8x - 6x = 28 - 4

2x = 24

x = 24/2

x = 12°

Read more about Alternate Angles at; brainly.com/question/24839702

#SPJ1

4 0

1 year ago