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netineya [11]
2 years ago
8

Perform the indicated operation. h(n)=n-3 g(n)=-2n² + 2 Find (hºg)(n)

Mathematics
1 answer:
Anni [7]2 years ago
3 0

Step-by-step explanation:

h(n) = n - 3 \\ g(n) =  - 2 {n}^{2}  + 2 \\  \\ (h.g)(n) = h(n).g(n)  \\  = (n - 3).( - 2 {n}^{2}  + 2) \\  = n( - 2 {n}^{2}  + 2) - 3( - 2 {n}^{2}  + 2) \\  =  - 2 {n}^{3}  + 2n + 6{n}^{2}   - 6 \\    \red{\boxed {\bold{\therefore \: (h.g)(n) = - 2 {n}^{3}+ 6{n}^{2} + 2n  - 6}}}

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Answer:

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Step-by-step explanation:

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2 years ago
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3 years ago
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2 years ago
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zheka24 [161]

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Answer:

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Step-by-step explanation:

There are an infinite number of rational numbers between any pair of numbers you name. These two number have the decimal values ...

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If you like, you can convert these numbers to ones with a common denominator (56).

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