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3 years ago

Perform the indicated operation. h(n)=n-3 g(n)=-2n² + 2 Find (hºg)(n)

Mathematics

1 answer:

Anni [7]3 years ago

3 0

Step-by-step explanation:

$h(n) = n - 3 \\ g(n) = - 2 {n}^{2} + 2 \\ \\ (h.g)(n) = h(n).g(n) \\ = (n - 3).( - 2 {n}^{2} + 2) \\ = n( - 2 {n}^{2} + 2) - 3( - 2 {n}^{2} + 2) \\ = - 2 {n}^{3} + 2n + 6{n}^{2} - 6 \\ \red{\boxed {\bold{\therefore \: (h.g)(n) = - 2 {n}^{3}+ 6{n}^{2} + 2n - 6}}}$

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Please help ASAP. Thanks so much.

sesenic [268]

C is the answer

4,-14

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3 years ago

Rewrite f(x) = x^2 + 4x -12 in the form that would most easily help you identify

ANEK [815]

Answer:

A. $f(x)=(x+6)(x-2)$

Step-by-step explanation:

Given function:

$f(x)=x^2+4x-12$

To rewrite the equation such that the zeros of the function can be easily identified.

Solution:

In order to find the zeros of the given quadratic function, we will use factorization by splitting up the middle term.

We have:

$f(x)=x^2+4x-12$

Splitting $4x$ into two term such that the sum of the two terms = $4x$ (middle term) and the product of the two terms is = $-12x^2$ (product of first and last term)

The terms are $6x,-2x$ as their sum = $4x$ and their product = $-12x^2$

So, we have:

$f(x)=x^2+6x-2x-12$

Factoring in pairs of first two terms and last two terms by factoring out their G.C.F.

$f(x)=x(x+6)-2(x+6)$

Since $(x+6)$ is a common term, we can factor it out further.

$f(x)=(x+6)(x-2)$ (Answer)

From the above function, we can identify that the zeros of the function are -6 and 2.

4 0

3 years ago

Read 2 more answers

I need help with this question.

dmitriy555 [2]

-56z+28? 56+28= 84 so your answer is d

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3 years ago

Determine whether each sequence is an arithmetic sequence. Write yes or no. Explain. 7, 10, 13, 16, ...

kvv77 [185]

Answer:

The given sequence is an arithmetic sequence.

Step-by-step explanation:

Given sequence is:

7, 10, 13, 16, ...

Here

$a_1 = 7\\a_2 = 10\\a_3 = 13\\a_4 = 16$

In order for a sequence to be an arithmetic sequence the common difference between the consecutive terms of the sequence should be same. Common difference is denoted by d.

So,

$d = a_2 - a_1 = 10-7 = 3\\d = a_3 - a_2 = 13-10 = 3\\d = a_4-a_3 = 16-13 = 3$