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BaLLatris [955]
3 years ago
5

Someone tell me where everyone is going right please !!

Mathematics
2 answers:
Anastasy [175]3 years ago
6 0

9514 1404 393

Explanation:

The problem statement tells you the meaning of t. It is minutes after Riko leaves. 0 ≤ t < 52.5 is the answer to the question regarding the interval Riko is behind Yuto. It means Riko is behind Yuto for 52.5 minutes after she leaves their house.

t will not be negative because time moves forward. Here, we're only counting time <em>after Riko leaves the house</em>. A negative value for t would refer to a time before Riko leaves the house, which is irrelevant in this problem.*

_____

* One might argue that Riko is behind Yuto for all values of time <em>after Yuto leaves the house</em>, which would be for -21 < t < 52.5. The concept of "behind Yuto" has no meaning except in that interval.

Molodets [167]3 years ago
5 0

Answer:

again again again hello or merhaba(hello)

speed = path / time

so we can say this;

speed × time = path

note;

two speeds in different directions add up

and

two speeds in the same direction subtract

our speeds are in the same direction so we subtract

0.35 - 0.25 = 0.10 speed

and our path is 5.25 miles because there are 5.25 miles between Yuto and Rico

when will they be in the same place now?

<h3>Let's solve with the formul;</h3>

<u>speed </u><u>×</u><u> </u><u>time </u><u>=</u><u> </u><u>path </u>

<u>0</u><u>.</u><u>1</u><u>0</u><u> </u><u>×</u><u> </u><u>time </u><u>=</u><u> </u><u>5</u><u>.</u><u>2</u><u>5</u><u> </u><u>miles</u>

<u>in this equation we find the time 52.</u><u>5</u><u> </u><u>minutes</u>

<u>After 52.5 minutes they will be in the same place but before 52.5 minutes Riko will be behind </u><u>Yuto</u>

<h3><u>When Riko was behind Yuto;</u></h3>

<u>0</u><u>≤</u><u> </u><u>t </u><u>≤</u><u> </u><u>5</u><u>2</u><u>,</u><u>5</u><u> </u><u> </u><u>(</u><u> </u><u>this is our equation of time)</u>

<h2><u>now the second question?</u></h2>

<h3><u>Why can't t be less than 0?</u></h3>

<u>because time cannot take a negative value, as soon as they start moving, time passes and this cannot take a negative </u><u>value</u>

<u>GOOD </u><u>LUCK</u><u> </u><u>:</u><u>D</u>

Step-by-step explanation:

greetings from Turkey (≧▽≦)

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