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Yuri [45]
3 years ago
13

Help with math question

Mathematics
1 answer:
NNADVOKAT [17]3 years ago
6 0

Well

You want to calculate the interest on $1000 at 3.5% interest per month after 3 year(s).

The formula we'll use for this is the simple interest formula, or:

Where: P is the principal amount, $1000.00.

r is the interest rate, 3.5% per month, or in decimal form, 3.5/100=0.035.

t is the time involved, 3....year(s) time periods.

Since your interest rate is "per month" and you gave your time interval in "year(s)" we need to convert your time interval into "month" as well.

Do this by multiplying your time, 3 year(s), by 12, since there's 12 months in 1 year.

So, t is 36....month time periods.

To find the simple interest, we multiply 1000 × 0.035 × 36 to get that:

The interest is: $1260.00

Hope i could help

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A community theater sells about 150 tickets to a play each week when it charges $20 per ticket.
Marta_Voda [28]

Answer:

  • r = 12.5p(32 -p)
  • $16 per ticket
  • $3200 maximum revenue

Step-by-step explanation:

The number of tickets sold (q) at some price p is apparently ...

  q = 150 + 25(20 -p)/2 = 150 +250 -12.5p

  q = 12.5(32 -p)

The revenue is the product of the price and the number of tickets sold:

  r = pq

  r = 12.5p(32 -p) . . . . revenue equation

__

The maximum of revenue will be on the line of symmetry of this quadratic function, which is halfway between the zeros at p=0 and p=32. Revenue will be maximized when ...

  p = (0 +32)/2 = 16

The theater should charge $16 per ticket.

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Maximum revenue will be found by using the above revenue function with p=16.

  r = 12.5(16)(32 -16) = $3200 . . . . maximum revenue

_____

<em>Additional comment</em>

The number of tickets sold at $16 will be ...

  q = 12.5(32 -16) = 200

It might also be noted that if there are variable costs involved, maximum revenue may not correspond to maximum profit.

5 0
2 years ago
Need help bad don't know how to solve. I don't get this math at all!
Verizon [17]
Where's the problem?

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