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vodka [1.7K]
3 years ago
10

What is zero of the polynomial and example

Mathematics
1 answer:
stich3 [128]3 years ago
8 0
<span> Binomials and trinomials are two types of polynomials. The first has two terms and the second has three.</span>
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The triangles shown below must be congruent.<br> O True<br> O False
azamat
The triangles are congruent because of the interior angles are all congruent. If you were to turn one of the triangles all of the angles would match.
8 0
2 years ago
Read 2 more answers
X-y+z for x= 1,y=6,z=1
adell [148]

Answer:

I'm glad you asked!

Step-by-step explanation:

x = 1.So the starting number is 1.

y=6.So it is 1-6.

z = 1.So it is now 1 - 6+1.

1-6+1 = -4.Your final answer is -4.

6 0
3 years ago
A piston rises to 5 cm and falls to 3 cm in such a way that it returns to the maximal height three times every two seconds. If w
sveticcg [70]

Answer:

(1 cm)cos3πt

Step-by-step explanation:

Since the piston starts at its maximal height and returns to its maximal height three times evert 2 seconds, it is modelled by a cosine functions, since a cosine function starts at its maximum point. So, its height h = Acos2πft

where A = amplitude of the oscillation and f = frequency of oscillation and t = time of propagation of oscillation.

Now, since the piston rises in such a way that it returns to the maximal height three times every two seconds, its frequency, f = number of oscillations/time taken for oscillation where number of oscillations = 3 and time taken for oscillations  = 2 s

So, f = 3/2 s =1.5 /s = 1.5 Hz

Also, since the the piston moves between 3 cm and 5 cm, the distance between its maximum displacement(crest) of 5 cm and minimum displacement(trough) of 3 cm is H = 5 cm - 3 cm = 2 cm. So its amplitude, A = H/2 = 2 cm/2 = 1 cm

h = Acos2πft

= (1 cm)cos2π(1.5Hz)t

= (1 cm)cos3πt

7 0
3 years ago
What is the value of t in this equation?<br> 3t=t+3
Lera25 [3.4K]
3t=t+3\\&#10;2t=3\\&#10;t=\dfrac{3}{2}
8 0
3 years ago
I'll give brainliest ​
Tpy6a [65]

Given:

\angle a and \angle b are complementary angles.

\angle a=32^\circ

To find:

The measure of \angle b.

Solution:

According to the definition of the complimentary angles, the sum of two complementary angles is always 90 degree.

It is given that, \angle a and \angle b are complementary angles. So,

\angle a+\angle b=90^\circ

32^\circ+\angle b=90^\circ

\angle b=90^\circ-32^\circ

\angle b=58^\circ

Therefore, the measure of \angle b is 58°.

3 0
3 years ago
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