Simplify 7x 42 / x^2 13x 42

2 answers:

7 0

$\frac{7x 42}{x^{2}13x42 } = \frac{7x}{ x^{2} 13x} = \frac{7x}{13 x^{3} } = \frac{7}{13 x^{2} }$

The answer is $\frac{7}{13 x^{2} }$

Rama09 [41]2 years ago

4 0

That is not an answer choice...

Here is the answer 7/x+7

Now here is why: You have to use your box method to find out the 2 x's that fit together for the quadratic that is in the denominator. From what I did I got (x+6)(x+7). Now simplifying the numerator is just simply 7(x+6). Now both the numerator and the denominator have the factor (x+6) so you simply cancel, or "cross" them out of the problem. Now you are left with 7/x+7.

Your welcome :)

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For each day in New England, the probability that it is mostly cloudy is 0.10 . Cindi is planning to go leaf watching, and her f

kolbaska11 [484]

Answer:

0,37

Step-by-step explanation:

It will be easier if we noun the events.

A= Cindi's friend comes to England.

B= New England is mostly cloudly.

We are searching the probability of just A doesn´t happen or just A happens but not B.

The probability of A doesn´t happen is one minus the probability of A:

$=(A^{|} )=1-P(A)=1-0.7=0.3$

The events A and B are independent for this reason the probability than both occurs is the product of the probability of each event. It means:

$P(A \cap B)= P(A)P(B)=0.1*0.7=0.07$

The probability of A doesn´t happen or A and B happen is:

$P(A^{|} \cup (A \cap B))= P(A^{|} )+P (A \cap B)-P(A^{|} \cap A\cap B)=0.3+0.07-0=0.37$

Conclusively we have to rest the probability of A doesn´t happen and A and B happen, but A happens and doesn´t happen and the same time is impossible. For this reason, we have the same result.

$P(A^{|} \cup (A \cap B))-P(A^{|} \cap A\cap B)=0.37-0=0.38$