The AWNSER to the question is .3
Answer:
It looks blurry and faded
Step-by-step explanation:
I got ECHA... hope it's right:)
You're thinking b=1 will always give an integer, certainly true.
Then you think b=-1 will also always give an integer, so
Answer: ±1
Then you remember that a/b may not be a reduced fraction, so other bs beside the unit make give integers. The condition for an integer is
b | a
read 'b divides a' meaning a is a multiple of b.
Then you realize that a and b might not even b integers themselves.
Let's say the above answer is correct with the additional criteria that a and b are integers with no common factors.
