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alexgriva [62]
3 years ago
12

A pair of laces has a price tag of $7.00. The

Mathematics
1 answer:
Reil [10]3 years ago
3 0

Answer:

The answer is C. $7.56

Step-by-step explanation:

7(0.08 + 1) = 7.56

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Autum school holding a voleturing challeng. Students are encouraged to volunteer for at least 1 1/2 hours per week. Volenteers a
Pani-rosa [81]

Given :

Challenge given is to volunteer for about 1 1/2 hours per week .

Autum did at a rate of 6 3/4 hours per week .

To Find :

The comparison ( ratio )  her volunteers rate with the challenge rate .

Solution :

Simplifying challenge rate in in normal fraction , 1\dfrac{1}{2}=\dfrac{2+1}{2}=\dfrac{3}{2} .

Also , simplifying her rate , 6\dfrac{3}{4}=\dfrac{(6\times 4)+3}{4}=\dfrac{27}{4} .

Now , ratio of his work by challenge is :

R=\dfrac{\dfrac{27}{4}}{\dfrac{3}{2}}\\\\\\R=\dfrac{27\times 2}{4\times 3}\\\\R=\dfrac{9}{2}

Therefore , the ratio is 9/2 or 4 1/2 .

Hence , this is the required solution .

8 0
3 years ago
Read 2 more answers
(5a^2+6a+2)-(7a^2-7a-5)
krok68 [10]

For this case we must simplify the following expression:(5a^ 2 + 6a + 2) - (7a^ 2-7a-5) =

We eliminate the parentheses taking into account that:

- * + = -\\- * - = +

So:

5a ^ 2 + 6a + 2-7a ^ 2 + 7a + 5 =

We add similar terms taking into account that:

Equal signs are added and the same sign is placed.

Different signs are subtracted and the major sign is placed.

5a ^ 2-7a^2 + 6a + 7a +2 +5 =\\-2a ^ 2 + 13a + 7

Answer:

-2a ^ 2 + 13a + 7

8 0
3 years ago
Write and solve a real-word word problem in which there are 3 tables for every 8 chairs
Talja [164]

Answer:

tate is hosting a party and he has 23 people coming over. for every table he buys, 8 chairs come with it. how many tables should tate buy so that he can seat all of his guests?

Step-by-step explanation:

6 0
3 years ago
Find the six trigonometric function values for angle ∅ where its adjacent side is -9 and its hypotenuse is 41. (Theta is located
arsen [322]
Check the picture below.

\bf \textit{using the pythagorean theorem}
\\\\
c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
\sqrt{41^2-(-9)^2}=b\implies \sqrt{1681-81}=b\\\\\\ \sqrt{1600}=b\implies 40=b\\\\
-------------------------------

\bf sin(\theta )=\cfrac{\stackrel{opposite}{40}}{\stackrel{hypotenuse}{41}}\qquad~~  cos(\theta )=\cfrac{\stackrel{adjacent}{-9}}{\stackrel{hypotenuse}{41}}\qquad~~  tan(\theta )=\cfrac{\stackrel{opposite}{40}}{\stackrel{adjacent}{-9}}
\\\\\\
csc(\theta )=\cfrac{\stackrel{hypotenuse}{41}}{\stackrel{opposite}{40}}\qquad ~~sec(\theta )=\cfrac{\stackrel{hypotenuse}{41}}{\stackrel{adjacent}{-9}}\qquad ~~cot(\theta )=\cfrac{\stackrel{adjacent}{-9}}{\stackrel{opposite}{40}}

3 0
3 years ago
Line l has a slope of the line through which of the following pair of points is perpendicular to l?
Olenka [21]

Answer:

Step-by-step explanation:

I think its A

4 0
2 years ago
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