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xxTIMURxx [149]
4 years ago
7

PLEASE HELP BEEN HERE for 30 minutes. GET A EASY 30 POINTS!

Mathematics
2 answers:
Bogdan [553]4 years ago
7 0

Answer:

A

Step-by-step explanation:

kondor19780726 [428]4 years ago
6 0

the answer is A the first one

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The probability that it rains in London an any particular day is 0.2.
jasenka [17]

Answer:

It is 14.45 percent

Step-by-step explanation:

The first day is independent from the day before. Therefore the first day probability (of rain) is 20 percent.

The second day (depends on the previous day) rainfall probability is 85 percent.

Finally, the third day (it must be rainy to satisfy the total probability) rainfall probability is 85 percent.

The probability of having three consecutive days which are rainy:

P(all rainy)

=

0.20

×

0.85

×

0.85

=

0.1445

or 14.45 percent.

3 0
3 years ago
What is the value of x? 1 2 x + 2 = x - 1 4 A) - 2 9 B) - 9 2 C) 1 9 D) 9 2
Volgvan
X=1.3
Hope this helps I not I’m truly sorry
6 0
3 years ago
Show work for full credit and brainliest!<br> 6% of what # is 105
Savatey [412]

6% = 0.06

So

105 / 0.06 = 1750

Answer

6% of 1750 = 105

Hope that helps

7 0
3 years ago
Read 2 more answers
Find value of x .........
evablogger [386]

Answer:

efvnhrje gvrvrvrervern v

Step-by-step explanation:

rev er vkjernvenvlhrsknvjnjkasf vjknerjngjkre vner gnerhnv r ekbhjr grenve r v rneilkn,b n skbvn erh kbfdhbvt e hjbhdf sf trblkdfjbniutrjdfsvn dfj sajkdbverhdfsvsdfvdfsvdsfv dfv dfv dsf v df vdf v df vd fsv d fv dsf v dfv  dfv df v df v df vdf v fdnv fdnv dfn dfhd,sjbn trhjkgmfds,hhhhhhhhhhhhhhhh

5 0
3 years ago
Consider a triangle ABC like the one below. Suppose that =A110°, =b25, and =c4. (The figure is not drawn to scale.) Solve the tr
tamaranim1 [39]

Side a, angle B and angle C of triangle ABC are 26.6 units, 61.9 degrees and 8.1 degrees respectively.

<h3>What is the value of the missing angles and side?</h3>

Given that;

  • Angle A = 110°
  • Side b = 25
  • side c = 4
  • side a = ?
  • Angle B = ?
  • Angle C = ?

First we determine the length of side a

a = \sqrt{b^2-c^2-2bc*cos(A)}

We substitute our values into the above equationa = \sqrt{25^2-4^2-(2*25*4*cos(110)}\\\\a = 26.6

Side a has a length of 26.6 units.

B = cos^{-1}(\frac{a^2+c^2-b^2}{2ac}) \\\\B = cos^{-1}(\frac{26.63464^2+4^2-25^2}{2*26.63464*4}) \\\\B = 61.9

Angle B is 61.9 degrees.

C = cos^{-1}(\frac{a^2+b^2-c^2}{2ab} )\\\\C = cos^{-1}(\frac{26.63464^2+25^2-4^2}{2*26.63464*25} )\\\\C =8.1

Angle C is 8.1 degrees.

Therefore, side a, angle b and angle c of the triangle ABC are 26.6 units, 61.9 degrees and 8.1 degrees respectively.

Learn more about triangles here: brainly.com/question/14882091

#SPJ1

5 0
2 years ago
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