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xxTIMURxx [149]
3 years ago
7

PLEASE HELP BEEN HERE for 30 minutes. GET A EASY 30 POINTS!

Mathematics
2 answers:
Bogdan [553]3 years ago
7 0

Answer:

A

Step-by-step explanation:

kondor19780726 [428]3 years ago
6 0

the answer is A the first one

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The equal symbol with the wave meat "is Congeruent to"
Strike441 [17]

Answer:

angle 5 is 61°

angle 7 is 61°

Step-by-step explanation:

1. angle 7 + angle 8 = 90° Because they are complementary angles

2. Because of point 1 above, angle 5 + angle 6 = 90°

3. since given angle 6 = 29°

so, angle 5 = 90° - 29° = 61°

4. since given angle 5 = angle 8

so, angle 8 = 61°

5. from point 1 above,

angle 7 + 61° = 90°

so angle 7 = 29°

6 0
3 years ago
What is the f(n) runtime of the following pseudocode: sum = 0 for A = N/2 downto 1 for B = 1 to 4N increment sum by B
nikitadnepr [17]

Answer:

f(N) = 2+ N/2 + 6N² units of time.

Step-by-step explanation:

Assigning 0 to the variable sum takes one unit of time.

Each time you increment sum by B, you need to call the value of sum, sum it to B and assign it to sum, which takes three units of time in total. You are repeating this process for each value of B which ranges from 1 to 4n and for each value of A which ranges from 1 to n/2. Opening the FOR takes also another unit of time, so, as a result, we have

f(N) 1 + 1 (open the FOR in A)+ N/2*(1 (open the FOR in B) + 4N*3) = 2+ N/2 + 6N² units of time. It has order complexity O(N²).

5 0
3 years ago
What changes in the parent graph y= |x| would you see if you graphed y= |x+3| ?
Hunter-Best [27]

Answer:

The graph is shifted 3 units to the left

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Let log_(b)A=3; log_(b)C=2; log_(b)D=5 what is the value of log_(b)((A^(5)C^(2))/(D^(6)))
Colt1911 [192]

Answer:

-11

Step-by-step explanation:

Given

\log_bA=3\\ \\\log_bC=2\\ \\\log_bD=5

Use properties:

\log_b(A\cdot C)=\log_bA+\log_bC\\ \\\log_b\dfrac{A}{C}=\log_bA-\log_bC\\ \\\log_bA^k=k\log_bA

Thus,

\log_b\dfrac{A^5\cdot C^2}{D^6}\\ \\=\log_b(A^5\cdot C^2)-\log_bD^6\\ \\=\log_bA^5+\log_bC^2-\log_bD^6\\ \\=5\log_bA+2\log_bC-6\log_bD\\ \\=5\cdot 3+2\cdot 2-6\cdot 5\\ \\=15+4-30\\ \\=-11

3 0
3 years ago
Please help me solve this question
xxMikexx [17]
What is your tabletop asking us today?
5 0
3 years ago
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