An elementary school has 1558 students. There are 48 classes. Estimate the number of students in each class

1 answer:

8 0

$number\ of\ students\ in\ each\ class=\frac{number\ of \ all\ students}{number\ of\ classes}\\\\
number\ of\ students\ in\ each\ class=\frac{1558}{48}=32.45\\\\In\ one\ class\ there\ are\ something\ about\ 32\ students.$

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F(x)=x^3-2x+6 g(x)=2x^3+3x^2-4x+2 Find (f-g)(x).

____ [38]

(f-g)(x) = f(x) - g(x)
= (x^3 -2x+6) - (2x^3+3x^2-4x+2)
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= (1-2)x^3 -3x^2 +(-2+4)x +(6-2) . . . . . combine like terms

(f-g)(x) = -x^3 -3x^2 +2x +4

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3 years ago

Find the value of x then classify the triangle by its angles

Neporo4naja [7]

Answer:

Step-by-step explanation:

3x + x + 60 = 180.

first, we add the x's together.

4x + 60 = 180

then we see if they all have a common multiple. in this case, they do. they are all divisible by 4, so we can use that.

x + 15 = 45

then, just subtract 15 from both sides, that way we get the variable by itself.

x = 30

also, it is a right triangle. the top angle (3x) multiplied by 3 is 90. any triangle that has a 90 degree angle is automatically a right triangle.

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3 years ago

Read 2 more answers

Find the perimeter of the quadrilateral.

levacccp [35]

Question:

Find the perimeter of the quadrilateral. if x = 2 the perimeter is ___ inched.

The complete figure of this question is attached below

Answer:

<h3>The perimeter of the quadrilateral is 129 inches</h3>

Solution:

The complete figure of this question is attached below

Given that, a quadrilateral with,

Side lengths are:

$4x^2 + 8x\ inches \\\\3x^2-5x+20\ inches \\\\7x + 30\ inches \\\\31\ inches$

The values of the side lengths when x = 2 are

$(4x^2+8x)=(4\times 2^2+8\times 2)=(4\times 4+16)=16+16=32\ inch\\\\(3x^2-5x+20)=(3\times 2^2-5\times 2+20)=(3\times 4-10+20)=12+10=22\ inch\\\\(7x+30)=(7\times 2+30)=14+30=44\ inch$